Answer:
Your answer is: D) Tinea Pedis
Explanation:
Hope this helped : )
4 Hz is the difference between 510 and the unknown.
<span>Therefore the unknown is either 514 or 506. </span>
<span>If 505 and 506 were struck together, the diff would be 1 Hz </span>
<span>If 505 and 514 were struck toghether, the diff would be 9 Hz which would be difficult to count accurately, </span>
<span>Therefore the unknown is 514</span>
Answer:
The width of the slit is 0.4 mm (0.00040 m).
Explanation:
From the Young's interference expression, we have;
(λ ÷ d) = (Δy ÷ D)
where λ is the wavelength of the light, D is the distance of the slit to the screen, d is the width of slit and Δy is the fringe separation.
Thus,
d = (Dλ) ÷ Δy
D = 3.30 m, Δy = 4.7 mm (0.0047 m) and λ = 563 nm (563 ×
m)
d = (3.30 × 563 ×
) ÷ (0.0047)
= 1.8579 ×
÷ 0.0047
= 0.0003951 m
d = 0.00040 m
The width of the slit is 0.4 mm (0.00040 m).
False. That's why sound cannot be heard in space.