WO3 + 3H2 → W + 3H2O

1 answer:

6 0

This problem is providing us with the reaction whereby tungsten is produced from tungsten (VI) oxide and hydrogen, so the percentage atom economy is required and found to be 64.3 % according to:

<h3>Atom economy:</h3>

In the ambit of green chemistry, atom economy is one of the twelve principles of green chemistry, and tell us how efficient a chemical process is, in terms of the necessary reactants, versus the yielded products. In the ideal case, it is 100 % meaning that all the reactants lead to the desired product.

However, when byproducts are present, this percentage dwindles and the idea is to reason how convenient the process is. In this case, we can calculate the atom economy, by simply dividing the atomic mass of tungsten by the addition of the molar mass of tungsten (VI) oxide and three times that of waters:

$\%A-E=\frac{183.84g/mol}{231.84g/mol+3*18.02g/mol} *100\%\\\\\%A-E=64.3\%$

Learn more about atom economy: brainly.com/question/25751649

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In what unit is formula mass expressed?

Illusion [34]

Italicized lowercase m

8 0

3 years ago

Write the net ionic equation for the precipitation reaction that occurs when aqueous solutions of potassium hydroxide and nickel

Gnom [1K]

<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of nickel (II) acetate and potassium hydroxide is given as:

$Ni(CH_3COO)_2(aq.)+2KOH(aq.)\rightarrow 2CH_3COOK(aq.)+Ni(NO_3)_2(s)$

Ionic form of the above equation follows:

$Ni^{2+}(aq.)+2CH_3COO^-(aq.)+2K^+(aq.)+2OH^-(aq.)\rightarrow 2CH_3COO^-(aq.)+2K^+(aq.)+Ni(OH)_2(s)$

As, acetate and potassium ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

$Ni^{2+}(aq.)+2OH^-(aq.)\rightarrow Ni(OH)_2(s)$

Hence, the net ionic equation is written above.

4 0

2 years ago

30,000 J of heat are added to 23.0 kg of steel to reach a final temperature of 140

kolbaska11 [484]

The initial temperature is 137.34 °C.

<u>Explanation:</u>

As the specific heat formula says that the heat energy required is directly proportional to the mass and change in temperature of the system.

Q = mcΔT

So, here the mass m is given as 23 kg, the specific heat of steel is given as c = 490 J/kg°C and the initial temperature is required to find with the final temperature being 140 °C. Also the heat energy required is 30,000 J.

ΔT = $\frac{Q}{mc}$