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anygoal [31]
2 years ago
12

A 12.0 V battery delivers a 0.40 A current to an electric motor that is connected across the battery terminals. What power is co

nsumed by the motor?
2.4 watts

30 watts

.03 watts

4.8 watts
Physics
1 answer:
zhannawk [14.2K]2 years ago
6 0

Answer:

4.8 watts

Explanation:

power = voltage * current = 12.0 * 0.40 = 4.8 watts

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A Lamborghini Aventador engine reaches its top speed from rest in 3 seconds. The engine performs 1,545,000 Joules of work in tha
nikitadnepr [17]

Answer:

W = 1.545E6 J   total work

P = W / t = 1.545E6 J / 3 sec = 5.15E5 J/sec = 515,000 J/sec  (Watts)

Using definition of power

5 0
2 years ago
Wheel A has a radius of R and wheel B has a radius of 2R. Wheel A has all the mass at the rim, while wheel B has the mass unifor
azamat

Answer:

Wheel A.

Explanation:

The lesser the moment of inertia, the greater the angular acceleration. Then, the moments of inertia of each wheel are described below:

Wheel A

I_{A} = M\cdot R^{2}

Wheel B

I_{B} = \frac{1}{2}\cdot M \cdot (2\cdot R)^{2}

I_{B} = 2\cdot M\cdot R^{2}

The wheel A accelerates faster in response to the torque.

3 0
3 years ago
NEED THIS ASAP
horrorfan [7]

Answer:

Energy is essentially work done by an object or on object.

From,

W = Fd

It's directly proportional to mass.

from,

K. E = 1/2mv²

Energy is directly proportional to mass.

P. E = mgh

Energy is directly proportional to mass.

H = mc∆T

Energy is directly proportional to mass.

Thus increasing mass will increase the energy also imparted on another object since all the above eqns show that relationship.

And for 2 moving bodies

K.Ei = K.Ef(energy conservation)

m1u²1 + m2u²2 = m1v²1 + m2v²2

The relationship is the same that the greater mass the greater the impact.

5 0
3 years ago
A sphere has surface area 1.25 m2, emissivity 1.0, and temperature 100.0°C. What is the rate at which it radiates heat into empt
Yuri [45]
The total power emitted by an object via radiation is:
P=A\epsilon \sigma T^4
where:
A is the surface of the object (in our problem, A=1.25 m^2
\epsilon is the emissivity of the object (in our problem, \epsilon=1)
\sigma = 5.67 \cdot 10^{-8} W/(m^2 K^4) is the Stefan-Boltzmann constant
T is the absolute temperature of the object, which in our case is T=100^{\circ} C=373 K

Substituting these values, we find the power emitted by radiation:
P=(1.25 m^2)(1.0)(5.67 \cdot 10^{-8}W/(m^2K^4)})(373 K)^4=1371 W = 1.4 kW
So, the correct answer is D.
6 0
3 years ago
If an object is projected upward with an initial velocity of 127 ft per? sec, its height h after t seconds is h equals negative
Stolb23 [73]
To determine the height of the object given the time, we simply use the given relation between height and time in the problem statement. It is given as:

h = -16t^2 + 127t

We substitute 55 seconds to t and obtain,

h = -16(55)^2 + 127(55)
h = - 41415
4 0
3 years ago
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