Newton's third law of motion. Because you are pushing the water backwards which will push you forwards
Answer:
50 j
Explanation:
W=Force*distance
W=10N*5M
W=50 NM
n*m = joules so you can say 50joules
Answer:
Ae/A* = 1.115
Explanation:
Let the reservoir pressure be 
Let the exit pressure be 
Ratio of reservoir pressure and exit pressure
= 3.182
For the above value of pressure ratio
Obtain the area ratio from the isentropic flow table
Ae/A* = 1.115
The value of pressure ratio is Ae/A* = 1.115
Answer: 0.53m
Explanation:
According to the equation of motion v²= v₀²+2as
Since the body is launched upward, the final velocity at the maximum height will be "zero" since the body will momentarily be at rest at the maximum height i.e v = 0
Initial velocity given (v₀) = 3.25 m/s
The body is also under the influence of gravity but the acceleration due to gravity will be negative being an upward force (a = -g) and the distance (s) will serve as our maximum height (h)
The equation of motion will.now become
V = v₀² -2gh
Where v = 0 v₀ = 3.25m/s g = 10m/s h = ?
0 = 3.25² - 2(10)h
0 = 10.56 - 20h
-10.56 = -20h
h = 10.56/20
h = 0.53m
Therefore, the maximum height, h (in meters), above the launch point that the basketball will achieve is 0.53m
Answer:
The wavelengths of C1 is 10.4m, A6 is 0.193m and B7 is 0.0861m
Explanation:
Using the formula V = f×λ . Then substitute the following values into the formula:
a) v=340m/s
f=32.7 Hz
λ=V ÷ f
= 340 ÷ 32.7
= 10.4m (3s.f)
b) λ=340 ÷ 1760
= 0.193m (3s.f)
c) λ=340÷3951.1
= 0.0861m (3s.f)
(Correct me if I am wrong)
