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tangare [24]
2 years ago
5

How to find distance when given mass time and force​

Physics
1 answer:
Yuri [45]2 years ago
7 0

Answer:

it is actually very easy & interesting. first write formula of force F=Mass×Acceleration . now see what are the unknowns , mass is known but acceleration is not . so find acceleration, a=velocity/time , but now again we dont know velocity, V= distance/time . subbing in all the values, Force=Mass×(distance/time^2)

Hope it helps if you have any problem feel free to ask.

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A particle with a mass of 6.64 × 10–27 kg and a charge of +3.20 × 10–19 C is accelerated from rest through a potential differenc
blondinia [14]

Answer:

Explanation:

Given that,

Mass m = 6.64×10^-27kg

Charge q = 3.2×10^-19C

Potential difference V =2.45×10^6V

Magnetic field B =1.6T

The force in a magnetic field is given as Force = q•(V×B)

Since V and B are perpendicular i.e 90°

Force =q•V•BSin90

F=q•V•B

So we need to find the velocity

Then, K•E is equal to work done by charge I.e K•E=U

K•E =½mV²

K•E =½ ×6.64×10^-27 V²

K•E = 3.32×10^-27 V²

U = q•V

U = 3.2×10^-19 × 2.45×10^6

U =7.84×10^-13

Then, K•E = U

3.32×10^-27V² = 7.84×10^-13

V² = 7.84×10^-13 / 3.32×10^-27

V² = 2.36×10^14

V=√2.36×10^14

V = 1.537×10^7 m/s

So, applying this to force in magnetic field

F=q•V•B

F= 3.2×10^-19 × 1.537×10^7 ×1.6

F = 7.87×10^-12 N

6 0
3 years ago
Read 2 more answers
How can humans activities affect the frequency and impact of natural disasters
denpristay [2]
Forest fires can be an impact 

8 0
3 years ago
Read 2 more answers
Consider the nearly circular orbit of Earth around the Sun as seen by a distant observer standing in the plane of the orbit. Wha
ikadub [295]

We have that the spring constant is mathematically given as

k=2.37*10^{11}N/m

Generally, the equation for angular velocity is mathematically given by

\omega=\sqrt{k}{m}

Where

k=spring constant

And

\omega =\frac{2\pi}{T}

Therefore

\frac{2\pi}{T}=\sqrt{k}{n}

Hence giving spring constant k

k=m((\frac{2 \pi}{T})^2

Generally

Mass of earth m=5.97*10^{24}

Period for on complete resolution of Earth around the Sun

T=365 days

T=365*24*3600

Therefore

k=(5.97*10^{24})((\frac{2 \pi}{365*24*3600})^2

k=2.37*10^{11}N/m

In conclusion

The effective spring constant of this simple harmonic motion is

k=2.37*10^{11}N/m

For more information on this visit

brainly.com/question/14159361

8 0
3 years ago
A contact force exists between two interacting objects that physically contact each other. a non-contact force exists when two i
Murrr4er [49]
True.

A contact force is a force between two objects that are physically in contact with each other: an example of a contact force is the normal reaction of a table supporting a book.

A non-contact force is a force between two objects that are not physically in contact with each other: an example of non-contact force is the gravitational attraction between the Earth and the Moon.
4 0
3 years ago
Read 2 more answers
Using -10 m/s2 for acceleration due to gravity, what would be the total displacement of the object if it took 8 seconds before h
ASHA 777 [7]
If it starts from 0m/s...
s=?
u=0
a=-10
t=8
s=ut +1/2at^2
so s=(0×8)+ (0.5×-10×64)
s=0+(32×-10)
s=32×-10
s=-320metres
6 0
3 years ago
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