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katovenus [111]
2 years ago
15

(Q012) Mafic minerals a. form rhyolite and granite. b. crystallize at a higher temperature than do silicic minerals. c. typicall

y crystallize last out of a melt. d. are rich in aluminum and sodium.
Chemistry
1 answer:
Archy [21]2 years ago
4 0

The property that can be ascribed to Mafic minerals from the options listed is that they typically crystallize last out of a melt.

<h3>What are Mafic minerals?</h3>

The term Mafic minerals is a term that embraces all those minerals that contain magnesium and iron. They are usually silicate minerals obtained from an igneous rock.

The property that can be ascribed to Mafic minerals from the options listed is that they typically crystallize last out of a melt.

Learn more about Mafic minerals: brainly.com/question/8908511

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URGENT CHEMISTRY EXPERT!
vovangra [49]

Answer:

Part 1: 7.42 mL; Part 2: 3Cu²⁺(aq) + 2PO₄³⁻(aq) ⟶ 2Cu₃(PO₄)₂(s)

Explanation:

Part 1. Volume of reactant

(a) Balanced chemical equation.

\rm 2Na_{3}PO_{4} + 3CuCl_{2} \longrightarrow Cu_{3}(PO_{4})_{2} + 6NaCl

(b) Moles of CuCl₂

\text{Moles of CuCl}_{2} =\text{ 16.7 mL CuCl}_{2} \times \dfrac{\text{0.200 mmol CCl}_{2}}{\text{1 mL CuCl}_{2}} =  \text{3.340 mmol CuCl}_{2}

(c) Moles of Na₃PO₄

The molar ratio is 2 mmol Na₃PO₄:3 mmol CuCl₂

\text{Moles of Na$_{3}$PO}_{4} =  \text{3.340 mmol CuCl}_{2} \times \dfrac{\text{2 mmol Na$_{3}$PO}_{4}}{\text{3 mmol CuCl}_{2}} =\text{2.227 mmol Na$_{3}$PO}_{4}

(d) Volume of Na₃PO₄

V = \text{2.227 mmol Na$_{3}$PO}_{4}\times \dfrac{\text{1 mL Na$_{3}$PO}_{4}}{\text{0.300 mmol Na$_{3}$PO}_{4}} = \text{7.42 mL Na$_{3}$PO}_{4} \\\\\text{The reaction requires $\large \boxed{\textbf{7.42 mL Na$_{3}$PO}_{4}}$}

Part 2. Net ionic equation

(a) Molecular equation

\rm 2Na_{3}PO_{4}(\text{aq}) + 3CuCl_{2}(\text{aq}) \longrightarrow Cu_{3}(PO_{4})_{2}(\text{s}) + 6NaCl(\text{aq})

(b) Ionic equation

You write molecular formulas for the solids, and you write the soluble ionic substances as ions.

According to the solubility rules, metal phosphates are insoluble.

6Na⁺(aq) + 2PO₄³⁻(aq) + 3Cu²⁺(aq) + 6Cl⁻(aq) ⟶ Cu₃(PO₄)₂(s) + 6Na⁺(aq) + 6Cl⁻(aq)  

(c) Net ionic equation

To get the net ionic equation, you cancel the ions that appear on each side of the ionic equation.

<u>6Na⁺(aq)</u> + 2PO₄³⁻(aq) + 3Cu²⁺(aq) + <u>6Cl⁻(aq)</u> ⟶ Cu₃(PO₄)₂(s) + <u>6Na⁺(aq)</u> + <u>6Cl⁻(aq)</u>  

The net ionic equation is

3Cu²⁺(aq) + 2PO₄³⁻(aq) ⟶ Cu₃(PO₄)₂(s)

7 0
3 years ago
What is the main purpose of using NaOH in the saponification reaction . NaOH works as the catalyst b. NaOH solution is the solve
Alex777 [14]

Answer:

C. NaOH acts as a reactant in the reaction

Explanation:

Because during the saponification process, Na+ replaces the H+ in the fatty acid been used for the saponification process

7 0
3 years ago
A student investigates the properties of an unknown liquid substance in a beaker. The student finds the substance has a mass of
shtirl [24]

Answer:

The substance is a mixture because it left a white powder in the beaker when boiled.

Explanation:

8 0
3 years ago
Determine the mass of each sample 1.55 kmol sulfur trioxide
xxMikexx [17]

Explanation:

Given parameters:

Number of moles of the sulfur trioxide = 1.55kmol = 1.55 x 10³mole

Unknown:

Mass of the sulfur trioxide = ?

Solution:

To solve for the mass of the sample of sulfur trioxide:

  •  Find the molar mass of the compound i.e SO₃

          atomic mass of S = 32g

                                    O = 16g

              molar mass = 32 + 3(16) = 80g/mol

  • Use the formula below:

           mass of SO₃ = number of moles x molar mass

           mass of SO₃ =  1.55 x 10³ x 80 = 124000g or 124kg

Learn more:

mole calculation  brainly.com/question/13064292

#learnwithBrainly

3 0
3 years ago
Define the following terms.<br> a. Capillary action<br> b. Chromatogram
jonny [76]

Answer:

<em>1</em><em>.</em><em>Capillary action is important for moving water (and all of the things that are dissolved in it) around. </em>

<em>2</em><em>.</em><em>the pattern formed on an adsorbent medium by the layers of components separated by chromatography. </em>

Explanation:

hope this help you

6 0
3 years ago
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