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Anika [276]
2 years ago
10

6) The best way to reduce force in a car wreck when impulse stays the same is to

Physics
1 answer:
UkoKoshka [18]2 years ago
3 0

Answer:

c. increase momentum

Explanation:

When cars bounce off each other, or rebound, there is a larger change in momentum and therefore a larger impulse. A larger impulse means that a greater force is experienced by the occupants of the cars. When cars crumple together, there is a smaller change in momentum and therefore a smaller impulse.

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Please help! Will mark brainliest.
iogann1982 [59]

Answer:

1122.8

Explanation:

12.73 kg x 9.8 m/s^2 x 9m

=1122.786

Rounded=1122.8

6 0
3 years ago
A car starts from rest and accelerates at 2.0 m/s2 for 10 seconds. What is the car's displacement at the end of 10 seconds?
makvit [3.9K]

Answer:

100m

Explanation:

Find the acceleration first

Then plot a simple speed time graph

7 0
3 years ago
Verify that the linear speed of an ultracentrifuge is about 0.50 km's, and Earth in its orbit is about 30 km/s by calculating:
FrozenT [24]

Answer:

a) Indeed, the linear speed of the ultracentrifuge is 0.524 kilometers per second.

b) Indeed, the linear speed of the Earth in its orbits about the Sun is approximately 30 kilometers per second.

Explanation:

The linear speed of the particle (v), measured in kilometers per second, rotating in a circular pattern is calculated by the following formula:

v = R\cdot \omega (1)

Where:

R - Radius, measured in kilometers.

\omega - Angular speed, measured in radians per second.

Now we proceed to calculate the linear speed of each element:

a) Ultracentrifuge

If we know that \omega \approx 5235.988\,\frac{rad}{s} and R = 1\times 10^{-4}\,km, then the linear velocity is:

v = (1\times 10^{-4}\,km)\cdot \left(5235.988\,\frac{rad}{s} \right)

v = 0.524\,\frac{km}{s}

Indeed, the linear speed of the ultracentrifuge is 0.524 kilometers per second.

b) Earth

The Earth is 150 million kilometers away from the Sun and takes 365 days to complete one revolution around the Sun. First, we calculate angular speed of the planet:

\omega = \frac{2\pi}{T} (2)

Where T is the period, measured in seconds.

If we know that T = 31536000\,s, then the angular speed of the Earth is:

\omega = \frac{2\pi}{31536000\,s}

\omega = 1.992\times 10^{-7}\,\frac{rad}{s}

Now, we determine the linear speed:

v = (1.5\times 10^{8}\,km)\cdot \left(1.992\times 10^{-7}\,\frac{rad}{s} \right)

v = 29.88\,\frac{km}{s}

Indeed, the linear speed of the Earth in its orbits about the Sun is approximately 30 kilometers per second.

6 0
2 years ago
A steel aircraft carrier is 403 m long when moving through the icy North Atlantic at a temperature of 1.22 °C. By how much does
Lorico [155]

Answer:

it expands by 11 cm.

Explanation:

First we need the coefficient of linear thermal expansion of steel

a = 12e-6/K

Now we use the equation for linear thermal expansion

L1 = L0 * (1 + a * (t1 - t0))

Where

L0: length before expansion

L1: expanded length

t0: temperature before expansion

t1: temperature expanded

L1 = 403 * (1 + 12e-6 * (24 - 1.22)) = 403.11 m

It expanded 11 cm.

8 0
3 years ago
What carries an electric current through a solution?
sashaice [31]
Free ions. Negative ions have one extra electron, positive ions are missing an electron. Negative ions give up their extra electron easily. I hope my answer has come to your help. God bless and have a nice day ahead! Feel free to ask more questions. 
8 0
3 years ago
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