1. 70 km/
2. 400 km/h
3. 100 km/h
Answer:
-1.82 °C
Explanation:
Step 1: Given data
- Mass of NaCl (solute): 33.9 g
- Mass of water (solvent): 578 g = 0.578 kg
- Freezing point depression constant for water (Kb): -1.82 °C/m
Step 2: Calculate the molality of the solution
We will use the following expression.
m = mass of solute / molar mass of solute × kg of solvent
m = 33.9 g / 58.44 g/mol × 0.578 kg
m = 1.00 m
Step 3: Calculate the freezing point depression (ΔT)
The freezing point depression is a colligative property that, for a non-dissociated solute, can be calculated using the following expression:
ΔT = Kb × m
ΔT = -1.82 °C/m × 1.00 m
ΔT = -1.82 °C
Explanation:
In order to justify Marian's statement we have to look at the '' Amount per serving calories'' ⇒
In food label A we can see that this value is 160 calories
In food label B we can see that this value is 50 calories
⇒ 160 calories is slightly more than three times 50 calories
Otherwise If we want to justify Johan statement we need to look at the '' serving size '' ⇒
In food label A we can see that the serving size is 1 cup (237 mL)
In food label B we can see that the serving size is
cup (56g)
Working with the information of the food label A we can write the following expression :
⇒ Looking at the value of ''
'' ⇒


If we look at the same amount of portion volume :
In
cup of food A we have 40 calories
In
cup of food B we have 50 calories
We could conclude that Food B has more calories.
That's how both claims could both be justified.
Appropriate units for the speed of a chemical reaction, the reaction rate, are M/s