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zmey [24]
2 years ago
9

What is redox in terms of oxygen? Give an example.

Chemistry
2 answers:
Zarrin [17]2 years ago
8 0

Explanation:

both reduction and oxidation are occurring simultaneously, this is known as a redox reaction. An oxidizing agent is substance which oxidizes something else. In the above example, the iron(III) oxide is the oxidizing agent. A reducing agent reduces something else

Ede4ka [16]2 years ago
7 0
<h2>ANSWER:</h2>

<u>The oxygen atoms undergo reduction, formally gaining electrons,</u> while the carbon atoms undergo oxidation, losing electrons. Thus oxygen is the oxidizing agent and carbon is the reducing agent in this reaction.

<em>I </em><em>HOPE</em><em> IT</em><em> WILL</em><em> HELP</em><em> YOU</em><em>.</em><em>.</em><em>.</em>

<em>darkprincess</em>

<em>#</em><em>c</em><em>a</em><em>r</em><em>r</em><em>y</em><em>o</em><em>n</em><em>l</em><em>e</em><em>r</em><em>a</em><em>n</em><em>i</em><em>n</em><em>g</em>

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Room temperature is usually considered to be 25°C. What is that in kelvins?
kotegsom [21]

Answer:

298.15 K.

Explanation:

Room temperature is generally taken to be 25 °C (around 77 °F). 0 °C is equivalent to 273.15 K, so we add 273.15 to 25 to find that room temperature is around 298.15 K

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3 years ago
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slamgirl [31]

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c.OF2

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3 years ago
Balance the following reaction and use the equation to calculate the ΔHrxn. C3H8(g) + O2(g) → CO2(g) + H2O(g) Round your answer
gladu [14]

The reaction corresponds to the combustion of propane (C3H8). The balanced reaction is:

C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)

The reaction enthalpy is given as:

ΔHrxn = ∑nΔH°f(products) - ∑ nΔH°f(reactants)

          = [3ΔH°f(CO2(g)) + 4ΔH°f(H2O(g)] - [1ΔH°f(C3H8(g)) + 5ΔH°f(O2(g)]

          = [3(-393.5) + 4(-241.8)] - [-103.9 + 5(0)] = -2043.8 kJ

The enthalpy for the combustion of propane is -2044 kJ

4 0
3 years ago
Why is a solution not a pure substance
Firlakuza [10]
It is not a pure substance, because a solution are mixed chemicals in a way that the molecules are not bonded with one another. Thus, separating them from compounds and elements, which are pure substances.
8 0
3 years ago
A lab team places 0.250g of an unknown solid acid in an Erlenmeyer flask. They neutralize the solid acid with 15.0ml of 0.210 M
Otrada [13]

Answer:

<u>Molar</u><u> </u><u>mass</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>unknown</u><u> </u><u>acid</u><u> </u><u>is</u><u> </u><u>7</u><u>9</u><u> </u><u>grams</u>

Explanation:

We have to first get moles in 15.0 ml of sodium hydroxide solution:

{ \sf{1 \: l \: of \:NaOH \: contains \: 0.210 \: moles }} \\ { \sf{0.015 \: l \: of \: NaOH \: contain \: (0.015 \times 0.210) \: moles }} \\  { \underline{ = 0.00315 \: moles \: of \: NaOH}}

since mole ratio of acid : base is 1 : 1, so;

moles of acid that reacted is <u>0</u><u>.</u><u>0</u><u>0</u><u>3</u><u>1</u><u>5</u><u> </u><u>m</u><u>o</u><u>l</u><u>e</u><u>s</u><u> </u><u>o</u><u>f</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>u</u><u>n</u><u>k</u><u>n</u><u>o</u><u>w</u><u>n</u><u> </u><u>a</u><u>c</u><u>i</u><u>d</u><u>.</u>

then we've to get molar mass:

{ \sf{0.00315 \: moles \: of \: acid \: weigh \: 0.250 \: g}} \\ { \sf{1 \: mole \: of \: acid \: weighs \: ( \frac{1 \times 0.250}{0.00315} ) \: g}} \\ { \underline{ = 79.4 \: g \approx79 \: grams}}

6 0
3 years ago
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