Question

A basketball player must jump 1.2m in the air in order to dunk. What is the total time he is in the air?

Answer 1

Answer:

0.98 [sec].

Explanation:

1) the time when the player is moving up equals the time the player falls, it can be 't'. Then

2) the equation of moving down can be written as

$\frac{g*t^2}{2} =h, \ where$

g=10 [m/s²], t - time, h - the given height.

3) according to the formula above the time spent to moving down is:

$t=\sqrt{\frac{2h}{g}};$

$t=\sqrt{\frac{2.4}{10}}=\sqrt{0.24} =0.49[s].$

4) finally, the total time is t*2=0.98[sec].