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stealth61 [152]
2 years ago
15

A light bulb operating at a dc voltage of 120 V has a power rating of 60 W. How much current is flowing through this bulb

Physics
1 answer:
densk [106]2 years ago
8 0
  • Voltage=V=120V
  • Power=P=60W

  • Current=I

\\ \rm\rightarrowtail I=\dfrac{P}{V}=\dfrac{60}{120}=\dfrac{1}{2}=0.5A

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In what direction would you head from New York state to find warmer temperatures
Anni [7]
Head south. If you traveled west, it would gradually get warmer because the Pacific Coast is warmer than the Atlantic. But the quickest change would be if you traveled south to North Carolina and there you would experience warmer temperatures.
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3 0
3 years ago
A wheel rotating about a fixed axis has a constant angular acceleration of 4.0 rad/s2. In a 4.0-s interval the wheel turns throu
Nady [450]

Answer:

The  time interval is  t =  3 \ s

Explanation:

From the question we are told that

    The angular acceleration is  \alpha  =  4.0 \ rad/s^2

     The  time taken is  t  =  4.0 \ s

      The angular displacement is  \theta  = 80 \ radians

     

The angular displacement can be represented by the second equation of motion as shown below

          \theta =  w_i t  +  \frac{1}{2} \alpha t^2

where  w_i is the initial velocity at the start of the 4 second interval

So substituting values

        80 =  w_i *  4 + 0.5 *  4.0 *  (4^2)

=>    w_i  =  12 \ rad/s

Now considering this motion starting from the start point (that is rest ) we have

       w__{4.0 }} =  w__{0}} +  \alpha  * t

Where  w__{0}} is the angular velocity at rest which is zero  and  w__{4}} is the angular velocity after 4.0 second which is calculated as 12 rad/s s

        12 =  0  + 4 t

=>       t =  3 \ s

4 0
2 years ago
In a butcher shop, a horizontal steel bar of mass 4.94 kg and length 1.46 m is supported by two vertical wires attached to its e
mojhsa [17]

Answer:

Tension in right wire = 25.9N

Explanation:

I have attached a free body diagram to depict this question.

From the diagram, i have labelled the tensions in the strings T1 and T2.

While i labelled the weight of the bar as Wb and weight of sausage as Ws.

Now, when solving a problem like this we want to first remember that the beam is static; meaning it is not moving. From simple physics, this means that the sum of the forces in the y direction equals zero (i.e. the total downward forces equal the total upward forces)

Thus, from the diagram, the upward forces are T1 and T2 while the downward forces are Ws and Wb.

Thus;

T1 + T2 = Wb + Ws

We know that mass of bar = 4.94kg. Thus, Weight of bar(Wb) = mg = 4.94 x 9.81 = 48.46N

Also, weight of sausage (Ws) = mg = 2.49 x 9.81 = 24.43N

Thus,

T1 + T2 = 48.46N + 24.43

T1 + T2 = 72.89N - - - - - (eq 1)

Now, let's take moments about the left end of the bar.

The maximum weight of the bar will act at the centre, so distance from the Wb to left end = 1.46/2 = 0.73m

So, moments about left end;

T2 x 1.46 = (Wb x 0.73) + (Ws x 0.1)

1.46T2 = (48.46 x 0.73) + (24.43 x 0.1)

1.46T2 = 35.373 + 2.443

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3 0
3 years ago
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Korvikt [17]

Answer:

The strength of the electric field is 1.35\times10^{4}\ N/C.

Explanation:

Given that,

Speed v= 5.05\times10^{5}\ m/s

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Using equation of motion

v = u+at

5.05\times10^{5}=0+a\times3.90\times10^{-7}

a =\dfrac{5.05\times10^{5}}{3.90\times10^{-7}}

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Using relation of newton's second law and electric force

F= ma=qE

ma = qE

E=\dfrac{ma}{q}

Put the value into the formula

E=\dfrac{1.67\times10^{-27}\times1.29\times10^{12}}{1.6\times10^{-19}}

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