Answer:
(S)−1−iodo−2−methylbutane
Explanation:
This reaction involves the substitution of iodine for bromine in (S)−1−bromo−2−methylbutane. The reaction proceeds with retention of configuration because the product is (S)−1−iodo−2−methylbutane. There is no change in the configuration of the product compound when the reaction is carried out in acetone which is a polar aprotic solvent. The reaction is shown in the image attached.
Answer :
(1) The number of valence electrons present in the compound is, 20
(2) The number of bonded electrons present in the compound is, 16
(3) The number of lone pair electrons present in the compound is, 4
(4) The number of single bonds present in the compound is, 8
Explanation :
Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.
In the Lewis-dot structure the valance electrons are shown by 'dot'.
The given molecule is,
As we know that carbon has '4' valence electrons, hydrogen has '1' valence electrons and oxygen has '6' valence electrons.
Therefore, the total number of valence electrons in = 2(4) + 6(1) + 6 = 20
According to Lewis-dot structure, there are 16 number of bonding electrons and 4 number of non-bonding electrons or lone pair of electrons.
The Lewis-dot structure of is shown below.
