Answer:
B. The maximum angle decreases
Explanation:
If θ be the maximum angle of a slope that allows a crate placed on it to remain at rest , following condition exists .
tanθ = μ , θ is called angle of repose . μ is coefficient of static friction .
So the tan of angle of repose θ is proportional to coefficient of static friction.
If coefficient of static friction is less than .7 , naturally angle of repose will also become less ,ie, it at lower angle of inclination , the object will start slipping .
As per the question the color of laser light is given as red.
If we arrange all the electromagnetic waves in the decreasing order of frequency ,then the electromagnetic spectrum contains gamma ray as the first which is followed by all other electromagnetic waves according to their frequency.
The visible light ranges from 400 nm to 700 nm which contains sunlight i.e white colors with it's constituent colors starting from violet to red. The red color is the longest wavelength part of the visible region.
The wavelength of visible light is longer than ultraviolet wave but smaller than infrared radiation. Except the bisible region,the color of radiation is invisible to eye.
As per the question the color of emiited laser radiation is red .Hence it must lie in the visible region of the electromagnetic spectrum.
The force ffrom the ground that holds the rock up and prevents her from falling through the gound, unless the ground breaks.
1.
Answer:
N = 77
Explanation:
1) As we know that Tension in the wire is given as
T = 2000 N
now mass per unit length of the wire is given as


Now fundamental frequency is given as



now highest frequency is given as 10000 Hz
so total harmonics is given as


2.
Answer:
D) 7.14 Hz
Explanation:
As we know that
speed = (frequency)(wavelength)
given that
speed = 400 m/s
wavelength = 28 m
so frequency is given as


now if wavelength is doubled then we will have

new frequency will be


3.
Answer:
Number of nodes = 4
A) 4
Explanation:
Number of nodes = number of harmonics + 1
so here we know that
number of harmonics = 3
Number of nodes = 3 + 1
Number of nodes = 4
4.
Answer:
C) 35.1 Hz
Explanation:
fundamental frequency in an organ pipe closed at one end is given as

here we know that
v = 345 m/s
L = 2.46 m
now we have


5.
Answer:
A) 570
Explanation:
Number of harmonics is given as



6.
Answer:

Explanation:
For fundamental frequency we know that

here we know that


now we have

