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noname [10]
2 years ago
15

Oxalic acid (h2c2o4) has a ka of 5. 9×10−2, while the hydrogen oxalate anion (hc2o−4) has a ka of 6. 1×10−5. Is an aqueous solut

ion of a hydrogen oxalate salt (e. G. Nahc2o4) acidic, basic, or neutral?
Chemistry
1 answer:
finlep [7]2 years ago
6 0

Resultant aqueous solution of a hydrogen oxalate salt is basic in nature.

<h3>What is pH?</h3>

pH scale is used to determine the acidity, basicity or neutral nature of any solution.

  • Values from 0 to 6.9 shows the acidity.
  • 7 shows the neutrality.
  • And 7.1 to 14 shows the basicity.

Chemical equation for the given salt in an aqueous solution will be shown as:

NaHC₂O₄ + H₂O → NaOH + H₂C₂O₄

From the equation it is clear that reaction produces-

  • NaOH which is a strong base and
  • H₂C₂O₄ oxalic acid which is a weak acid.

So that resultant solution is basic in nature.

Hence the aqueous solution of salt is basic.

To know more about basicity, visit the below link:
brainly.com/question/172153

#SPJ1

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When an atom gains an electron, the resulting particle is calledA) a proton.B) an anion.C) a cation.D) an isotope.E) none of the
MAVERICK [17]

Answer:

B) an anion

Explanation:

During bonding atoms may share electron or give out electron . In the case of electrovalent or ionic bonding, electron(s) is/are transferred from one atom to another . The atom that donate the electron are known as donor atom and the atom that receives the electron are known as receivers.

The atom that donate the electron becomes a cation(positively charged) as it lose it electron(s) while the receiver gains electron to become an anion which is a negatively charge ion.  

An example of such interaction is between a sodium atom and a chlorine atom.  The Na atom lose it electron to become positively charged(cation) while the chlorine atom gains electron to become negatively charged(anion). Both atom bond together losing and gaining electron to fulfill the octet rule.

Na+  +  Cl-   → NaCl

5 0
3 years ago
Consider the following equilibrium:H2CO3(aq) + H2O(l) H3O+(aq) + HCO3-1(aq).What is the correct equilibrium expression?
Vanyuwa [196]

The equilibrium expression shows the ratio between products and reactants. This expression is equal to the concentration of the products raised to its coefficient divided by the concentration of the reactants raised to its coefficient. The correct equilibrium expression for the given reaction is:<span>

<span>H2CO3(aq) + H2O(l) = H3O+(aq) + HCO3-1(aq)

Kc = [HCO3-1] [H3O+] / [H2O] [H2CO3]</span></span>

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3 years ago
How many amps are required to produce 75. 8 g of iron metal from a solution of aqueous iron(iii)chloride in 6. 75 hours?
Shalnov [3]

The amount of current required to produce 75. 8 g of iron metal from a solution of aqueous iron (iii)chloride in 6. 75 hours is 168.4A.

The amount of Current required to deposit a metal can be find out by using The Law of Equivalence. It states that the number of gram equivalents of each reactant and product is equal in a given reaction.

It can be found using the formula,

m = Z I t

where, m = mass of metal deposited = 75.8g

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             I is the current passed

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On subsituting in above formula,

75.8 = E I t / F

⇒ 75.8 = 0.0001 × I × 4500

⇒ I = 168.4 Ampere (A)

Hence, amount of current required to deposit a metal is 168.4A.

Learn more about Law of Equivalence here, brainly.com/question/13104984

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Marta_Voda [28]

Answer:

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