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noname [10]
2 years ago
15

Oxalic acid (h2c2o4) has a ka of 5. 9×10−2, while the hydrogen oxalate anion (hc2o−4) has a ka of 6. 1×10−5. Is an aqueous solut

ion of a hydrogen oxalate salt (e. G. Nahc2o4) acidic, basic, or neutral?
Chemistry
1 answer:
finlep [7]2 years ago
6 0

Resultant aqueous solution of a hydrogen oxalate salt is basic in nature.

<h3>What is pH?</h3>

pH scale is used to determine the acidity, basicity or neutral nature of any solution.

  • Values from 0 to 6.9 shows the acidity.
  • 7 shows the neutrality.
  • And 7.1 to 14 shows the basicity.

Chemical equation for the given salt in an aqueous solution will be shown as:

NaHC₂O₄ + H₂O → NaOH + H₂C₂O₄

From the equation it is clear that reaction produces-

  • NaOH which is a strong base and
  • H₂C₂O₄ oxalic acid which is a weak acid.

So that resultant solution is basic in nature.

Hence the aqueous solution of salt is basic.

To know more about basicity, visit the below link:
brainly.com/question/172153

#SPJ1

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3 years ago
How many molecules are in 0.55 moles of Cu(NO3)2?
xeze [42]
<h3>Answer:</h3>

3.3 × 10²³ molecules Cu(NO₃)₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

0.55 mol Cu(NO₃)₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                     \displaystyle 0.55 \ mol \ Cu(NO_3)_2(\frac{6.022 \cdot 10^{23} \ molecules \ Cu(NO_3)_2}{1 \ mol \ Cu(NO_3)_2})
  2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 3.3121 \cdot 10^{23} \ molecules \ Cu(NO_3)_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

3.3121 × 10²³ molecules Cu(NO₃)₂ ≈ 3.3 × 10²³ molecules Cu(NO₃)₂

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3 years ago
Mrs. Huang operates a soybean farm. She buys many supplies in bulk. Often the bulk products need to be custom mixed before Mrs.
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Answer: 18L

Explanation:

Solving this question would be easier by assigning variables.

so, let x = amount of 67% needed solution

Let y = amount of 42% needed solution.

From the question, we know that

x + y = 42 thus,

y = 42 - x

we also know that the pure herbicide in the 67% solution plus the herbicide I'm the 46% solution must be equal to the amount of pure herbicide in the final solution. Thus mathematically, we have

0.67x + 0.46y = 0.55*42

0.67x + 0.46y = 23.1

Remember, y = 42 - x, substituting this value, we have

0.67x + 0.46(42-x) = 23.1

0.67x + 19.32 - 0.46x = 23.1

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0.21x = 3.78

x = 18

.therefore the amount of 67% solution needed is 18L

8 0
3 years ago
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