D) If only 6.6 grams of water are produced, what is the percent yield?
Write out the balanced equation:
2C2H6 + 7O2 --> 4CO2 + 6H2O
Then, determine the limiting reagents:
16.8 grams of C2H6/30.06 g/mol of C2H6 = 0.46 mol
45.8 grams of O2/32 g/mol of O2 = 1.4 mol
0.46 mol of C2H6/2 = 0.23
1.4 mol of O2/7 = 0.20
<em>- Dioxygen is the limiting reagent. </em>
Find the theoretical molar yield of water:
There is a 7 mol of O2 to 6 mol of H2O ratio (according to the balanced equation).
<em>We can setup a proportion;</em>
7/6 = 0.23/x
0.196 = x
So, 0.196 mol of water will be produced.
How many grams of water will be produced in the reaction?
<em><u>0.196 mol of H2O x 18 g/mol of H2O = 3.53 grams of H2O </u></em>
Sample means for solutions 1 and 2 are 19.27 and 10.32 respectively
In semiconductor manufacturing,
The total for answer 1 is given by:
9.7+10.5+9.4+10.6+9.3+10.7+9.6+10.4+10.2+10.5 = 192.7
The sample size is 10 and provides us with
192.7/10 = 19.27
For solution 2, the sum is given by:
10.6+10.3+10.3+10.2+10.0+10.7+10.3+10.4+10.1+10.3 = 103.2
The sample size is 10, this gives us
103.2/10 = 10.32
The total for answer 2 is given by:
10.6+10.3+10.3+10.2+10.0+10.7+10.3+10.4+10.1+10.3 = 103.2
The sample size is 10 and provides us with
103.2/10 = 10.32
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In semiconductor manufacturing, wet chemical etching is often used to remove silicon from the backs of wafers prior to metalization. The etch rate is an important characteristic in this process and is known to follow a normal distribution. Two different etching solutions have been compared, using two random samples of 10 wafers for each solution. Assume the variances are equal. The etch rates are as follows (in mils per minute): Solution 1 Solution 2 9.7 10.6 10.5 10.3 9.4 10.3 10.6 10.2 9.3 10.0 10.7 10.7 9.6 10.3 10.4 10.4 10.2 10.1 10.5 10.3 Calculate sample means of solution 1 and solution 2
Ans: Elements in the same period have the same number of electron shells.
