The strength of the electric field 0.5 m from a 6 µc charge is n/c. (use k = 8.99 × 109 n•meters squared per coulomb squared and
1 answer:
The strength of the electric field will be 215760 NC⁻¹. The concept of the electric field strength is used in the problem.
<h3>What is electric file strength?</h3>The electric field strength is defined as the ratio of electric force and charge. Its unit is NC⁻¹.
The given data in the problem is;
E is the Electric Field Strength
k is the Colomb's constant = 8.99 x 10⁹ N.m²/C²
q is the magnitude of charge = 6 μC = 6 x 10⁻⁶ C
r is the distance = 0.5 m
The electric field strength is given by the formula;
Hence the strength of the electric field will be 215760 NC⁻¹.
To learn more about the electric field strength refer to the link;
You might be interested in
Answer:
West
Explanation:
m = Mass of car =
t = Time = 9 seconds
u = Initial velocity = 30 m/s
v = Final velocity = 0
Impulse is given by
The magnitude of the total impulse applied to the car to bring it to rest is .
The direction is towards west as the sign is negative.
We can solve the problem by using the first law of thermodynamics, which states that:
where
is the change in internal energy of the system
Q is the heat absorbed by the system
W is the work done by the system
In our problem, the heat absorbed by the system is Q=+194 kJ, while the work done is W=-120 kJ, where the negative sign means the work is done by the surroundings on the system. Therefore, the variation of internal energy is
where
Q is the heat absorbed by the system
W is the work done by the system
In our problem, the heat absorbed by the system is Q=+194 kJ, while the work done is W=-120 kJ, where the negative sign means the work is done by the surroundings on the system. Therefore, the variation of internal energy is