The strength of the electric field 0.5 m from a 6 µc charge is n/c. (use k = 8.99 × 109 n•meters squared per coulomb squared and

Question

2 years ago

8

round answer to the nearest whole number.)

1 answer:

Kruka [31] · Answer 1 · 2023-05-02T05:37:56+03:00

The strength of the electric field will be 215760 NC⁻¹. The concept of the electric field strength is used in the problem.

<h3>What is electric file strength?</h3>

The electric field strength is defined as the ratio of electric force and charge. Its unit is NC⁻¹.

The given data in the problem is;

E is the Electric Field Strength

k is the Colomb's constant = 8.99 x 10⁹ N.m²/C²

q is the magnitude of charge = 6 μC = 6 x 10⁻⁶ C

r is the distance = 0.5 m

The electric field strength is given by the formula;

$\rm E = \frac{Kq}{R^2} \\\\ \rm E = \frac{8 .99 \times 10^9 6 \times 10^6 }{(0.5)^2} \\\\ E=215760 \ NC^{-1}$

Hence the strength of the electric field will be 215760 NC⁻¹.

To learn more about the electric field strength refer to the link;