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mrs_skeptik [129]
2 years ago
12

Consider the reaction H2(g) I2(g) Double headed arrow. 2HI(g). What is the reaction quotient, Q, for this system when [H2] = 0.

100 M, [I2] = 0. 200 M, and [HI] = 3. 50 M? 87. 5 175 350 613.
Chemistry
1 answer:
Dima020 [189]2 years ago
5 0

The reaction for the formation of HI, at the given time, has a reaction quotient of 613.

What is the reaction quotient?

Reaction quotient is the ratio of the concentration of product and reactant raised to the stoichiometric power at a given time interval.

The chemical reaction for the formation of HI is given as:

\rm H_2\;+\;I_2\;\rightarrow\;2\;HI

The reaction quotient is given as:

\rm Q=\dfrac{[HI]^2}{[H_2]\;[I_2]}

The concentration of system at the time, t has been:

Hydrogen = 0.1 M

Iodine = 0.2 M

HI = 3.5 M

Substituting the values for reaction quotient:

\rm Q=\dfrac{(3.5)^2}{(0.1)(0.2)}\\ Q=613

The reaction quotient for the reaction is 613. Thus, option D is correct.

Learn more about the reaction quotient, here:

brainly.com/question/8205004

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Because it only needs one more electron to get to a full valence shell (8), so it really wants it and is pulling other electrons in. It also has to do with needing one more electron to fill the 2p shell. It is a small element which means its electrons are pulled tightly to the nucleus.

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Explain the meaning of each term in the symbol aXz
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AXz

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It is a chemical notation of nuclide

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8 0
3 years ago
PLEASE HELP QUICK AS POSSIBLE!!!!
GalinKa [24]

Answer:

4180J

Explanation:

(25.0g)(4.184J/g°C)(75°C-35.0°C)

(25.0g)(40.0°C)(4.184J/g°C)

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8 0
3 years ago
Consider the reaction of CaCN2 and water to produce CaCO3 and NH3 according to the reaction CaCN2 + 3H2O → CaCO3 + 2 NH3 . How m
adelina 88 [10]

Answer:

56 g. Option 3.

Explanation:

The reaction is: CaCN₂ + 3H₂O → CaCO₃ + 2 NH₃

1 mol of calcium cianide reacts with 3 moles of water in order to produce 1 mol of calcium carbonate and 2 moles of ammonia

We have the mass of each reactant, so let's convert the mass to moles:

45 g. 1mol / 80.08 g = 0.562 moles of cianide

45 g. 1mol / 18 g = 2.5 moles of water

The cianide is the limiting reactant:

3 moles of water need 1 mol of cianide to react

Then, 2.5 moles of water will need (2.5 . 1)/ 3 = 0.833 moles

As we have 0.562 moles of CN⁻ we don't have enough

We can work now, on the reaction:

Ratio is 1:1. Therefore 0.562 moles of cianide will produce 0.562 moles of carbonate

Let's convert the mass to moles to find the answer:

0.562 mol . 100.08 g / 1 mol = 56.2 g

8 0
2 years ago
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