Answer:
Intensive properties can be used to help identify a sample because these characteristics do not depend on the amount of sample, nor do they change according to conditions.
Explanation:
Intensive properties are bulk properties, which means they do not depend on the amount of matter that is present. Examples of intensive properties include:
Boiling Point
Density
State of Matter
Color
Melting Point
Odor
Temperature
Refractive Index
Luster
Hardness
Ductility
Malleability
Answer:
See image below
Explanation:
The image is labeled according to the sequence N'-Trp-Ser-Asg-Gly-Cys-His-COOH' which means that in the main chain of the peptide, the amino group of the Tryptophan and the carboxylic group of the Histidine are free and thus its charge depends on the pH; other groups that rely on the pH are the side groups of the Cysteine and the Histidine.
Overall, ionizable groups in this peptide are:
- Amino Group of the Tryptophan (pKa = 9.39)
- SH group of the Cysteine (pKa = 8.18)
- Secondary amine of the Histidine (pKa = 6.00)
- Carboxylic Group of the Histidine (pKa = 1.82)
Then, the amino group of Trp and SH group of Cys are protonated since the peptide is at a pH below the pKa. The secondary amine of the Histidine is deprotonated because the pH is greater than the pKa, as well with its carboxylic acid group.
First step is to calculate the mole of each element
that is;
carbon 97.6/12=8.13moles
hydrogen= 4.9/1=4.9 moles
oxygen 52/16=3.25 moles
nitrogen=45.5/14=3.25 moles
step two is to calculate the mole ratio by dividing with the smallest number of moles
that is divide each mole with 3.25moles
carbon=8.13/3.25 =5/2
hydrogen=4.9/3.25= 3/2
oxygen=3.25/3.25=1
nitrogen=3.25/3.25=1
step 3; multiply all the mole ratio by 2 to remove the fraction
carbon=5/2 x2 =5
hydrogen=3/2 x2=3
oxygen=1 x2=2
nitrogen =1x2=2
therefore the empirical formula is C5H3O2N2(answer c)
Answer:
Group 17, 2, 7, 7 electrons
Explanation: