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Vedmedyk [2.9K]
2 years ago
11

5. A weightlifter lifts a barbell of mass 50 kg to a height of 2m in 3s. (Take g = 9.8 m/s².) a) What is the weight of the barbe

ll? 5. A weightlifter lifts a barbell of mass 50 kg to a height of 2m in 3s . ( Take g = 9.8 m / s² . ) a ) What is the weight of the barbell ?
​
Physics
1 answer:
inysia [295]2 years ago
4 0

Answer:

490N

Explanation:

W=m×g

W=50×9.8=490N

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Which item could you use in place of an ammeter to demonstrate that a
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A 4.2-g bullet is fired at a speed of 370 m/s into a stationary lead block, which moves a distance of 1.2 m before coming to res
Natali5045456 [20]

Answer:

(a) F = 239.575 N (b) t = 0.00649s or 6.49 ms

Explanation:

(a) By law of energy conservation, the bullet kinetic energy will be transferred to work done on stopping it from moving.

Formula for Kinetic Energy E_k = \frac{mv^2}{2} where m is bullet mass, v is the velocity

Formula for work W = FS where F is the average force and S is the distance travelled.

E_k = W

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F = \frac{mv^2}{2S}

Substitute m = 4.2 g = 0.0042 kg, v = 370 m/s and S = 1.2 (m)

F = \frac{0.0042*370^2}{2*1.2} = 239.575 N

(b) If the force is constant, since the mass is constant and F = ma according to Newton's 2nd law, the acceleration on bullet is also constant

a = \frac{F}{m} = \frac{239.575}{0.0042} = 57041.67 (m/s^2)

We also have v(t) = v_0 + at

At the time the bullet is coming to rest, v(t) = 0, a = -57041.67 m/s^2

Therefore, 0 = 370 - 57041.67t

t = \frac{370}{57041.67} = 0.00649 s = 6.49 ms

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4 0
3 years ago
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Answer:

Because the bullet is smaller and has a sharp/pointy tip.

Explanation:

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3 years ago
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