If 0.25mg of atropine is in 1mL
so
0.50mg of atropine is in x
The ionic compound is CaSO4
KH₂PO₄ hydrolyzes as;
H₂PO₄⁻ + H₂O ↔ H₃PO₄ + OH⁻
Let x amount of H₂PO₄⁻ has reacted with water then,
Kb₁ = [H₃PO₄][OH⁻] / [H₂PO₄⁻]
[H₂PO₄⁻] = 0.8-x M
Kb₁ = x² / (0.8 - x)
Given Ka₁ = 7.5 x 10⁻³
so Kb₁ = 1 x 10⁻¹⁴ / (7.5 x 10⁻³) = 1.33 x 10⁻¹²
From this information:
1.33 x 10⁻¹² = x² / 0.8
x = [OH⁻] = 1.03 x 10⁻⁶ M
pOH = - log (1.03 x 10⁻⁶) = 5.99
pH = 14 - pOH = 14 - 5.99 = 8.01
<em>Octopus and squids breathe</em> <em>like </em><em>fishes </em><em>they </em><em>breathe </em><em>from </em><em>gills </em>
<em>so </em><em>even </em><em>octopus</em><em> and</em><em> squids</em><em> </em><em>breathe </em><em>through </em><em>gills </em><em>too.</em>
<em><u>maybe </u></em><em><u>this </u></em><em><u>answer</u></em><em><u> </u></em><em><u>would</u></em><em><u> </u></em><em><u>help</u></em><em><u> </u></em><em><u>u</u></em>