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Naily [24]
3 years ago
6

HEELLP PLEEASE!! When is a collision considered elastic?

Physics
1 answer:
marissa [1.9K]3 years ago
6 0
A perfectly elastic collision is defined as one in which there is no loss of kinetic energy in the collision. An inelastic collision is one in which part of the kinetic energy is changed to some other form of energy in the collision.
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State one advantage and disadvantage of friction
yuradex [85]

Answer:

  1. Advantage: Helps us to walk without slipping.
  2. Helps machines work

Disadvantage:

  1. We slip on a wet floor.
  2. Causes the smoothness of tires and smoothness of shoes soul.

5 0
3 years ago
What happens to the density of a fluid as the substance gains thernal energy
Natalka [10]

Density reduces

Explanation:

The density of a fluid will reduce as a substance gains more thermal energy. Heat is a form of thermal energy usually noticed as temperature differences in a matter.

  • When thermal energy is gained by a body, the temperature of the body rises.
  • The particles of the medium gains more kinetic energy.
  • This causes the substance to expand and it has more volume.
  • When a substance expands, it occupies more space.
  • The more the volume a body occupies, the lesser the density.
  • Expansion does not change the mass of the fluid but the volume changes.
  • This is why density decreases.

Learn more:

Density brainly.com/question/8441651

#learnwithBrainly

8 0
4 years ago
What is the magnitude of electrical force of attraction between an copper nucleus (29 protons) and its innermost electron if the
Agata [3.3K]
The charge of the copper nucleus is 29 times the charge of one proton:
Q=29 q= 29 \cdot 1.6 \cdot 10^{-19}C=4.64 \cdot 10^{-18}C
the charge of the electron is
e=-1.6 \cdot 10^{-19}C
and their separation is
r=1.0 \cdot 10^{-12} m

The magnitude of the electrostatic force between them is given by:
F=k_e  \frac{Qe}{r^2}
where k_e is the Coulomb's constant. If we substitute the numbers, we find (we can ignore the negative sign of the electron charge, since we are interested only in the magnitude of the force)
F=(8.99 \cdot 10^9 Nm^2C^{-2}) \frac{(4.64 \cdot 10^{-18}C)(1.6 \cdot 10^{-19}C)}{(1.0 \cdot 10^{-12} m)^2}=6.68 \cdot 10^{-3} N
3 0
4 years ago
How much soil is in a 5 cm to 9 cm deep hole?
vlabodo [156]
There is no soil in a hole

;)
6 0
3 years ago
Jose’s lab instructor gives him a solution of sodium phosphate that is buffered to a pH of 4. Because of an error that he made w
Kazeer [188]
I am thinking that maybe the problem is not with the calibration. It might be that the buffered solution is already expired since at this point the solution is already not stable and will give a different pH reading than what is expected.
7 0
3 years ago
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