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Sphinxa [80]
1 year ago
14

1.) A building has two lifts. One lift stops only at even numbered floors and the other stops only at odd numbered floors. What

is the advantage in operating the lifts in this manner, instead of both lifts stopping at every floor?
A. It makes sure that both the lifts are used for an equal number of trips.

B. It reduces the time taken to reach the required floor, as the lifts can move faster.

C. The total number of people that can be carried by two lifts is increased.

D. It makes sure that the lifts are always full while going up and while coming down.

2.) During winter in the temperate regions, days are short. Air samples taken since 1986, during winter in Canada which lies in the temperate region, show that the average atmospheric carbon dioxide concentration in winter is higher than it is in summer.
Which of the following statement is the most likely reason for this?

A. Plants breathe very little during the winter months.

B. More animals respire actively in the winter months.

C. The amount of photosynthesis taking place is less in winter.

D. Plants and animals use up stored food for respiration in winter.

3.) Parul has two colourless solutions P and Q. solution P turns red litmus paper blue. She mixes solutions P and Q together. On evaporation of the mixture she obtains crystals of common salt. Which of the following is solution Q likely to do?

A. Turn yellow turmeric paste red in colour

B. Cool down lime water when mixed with it.

C. Produce a gas when mixed with baking soda.

D. (Nothing can be said with just the given information.)​
Chemistry
1 answer:
dlinn [17]1 year ago
6 0

The answers for the following questions are given below

  1. the advantage in operating the lifts in this manner is: (B). It reduces the time taken to reach the required floor, as the lifts can move faster.
  2. The most likely reason for this is: (A). Plants breathe very little during the winter months.
  3. Solution Q likely to do: (D). (Nothing can be said with just the given information.)​

<h3>Meaning of Solution</h3>

A solution can be defined as a chemical mixture that is formed by two major components which are known as the solute and the solvent.

A solution based on its components varies in its type and function.

In conclusion, The answers for the following questions are given above.

Learn more about a Solution: brainly.com/question/25326161

#SPJ1

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Consider the followong balanced reaction. What mads in g of co2 can be formed from 288 mg of o2. Assume that there is excess c3h
Gwar [14]

<u>Answer:</u>

<em>0.264 g of CO_2 can be formed from 288 mg of O_2</em>

<u>Explanation:</u>

The balanced chemical equation is

2 C_3 H_7 OH+9 O_2> 6 CO_2+8 H_2 O

The conversions are  

Mass in mg O_2 is converted to mass in g O_2  

Mass in g O_2 is converted to moles O_2 by dividing with molar mass  

Moles O_2 is converted to moles CO_2  by using the mole ratio of O_2:CO_2 is 9 : 6

Moles CO_2  is converted to mass CO_2 by multiplying with molar mass CO_2

mass in mg O_2  > mass in g O_2 >moles O_2 > moles CO_2 > mass CO_2

288mg O_2 \times \frac{(1g O_2)}{(1000mg O_2 )} \times \frac {(1molO_2)}{(32gO_2 )}\times\frac {(6mol CO_2)}{(9mol O_2 )} \times \frac {(44.0 gCO_2)}{(1mol CO_2 )}

=0.264g (Answer)

7 0
3 years ago
HELP ASAP ILL GIVE BRAINIEST!!!
UNO [17]

Answer:

1. the group number of sodium is 1 and it is a metal

2. the group number of helium is 18 and it is a nonmetal

3. the group number of iodine is 17 and it is a nonmetal

4.the group number of calcium is 2 and it is a metal

5. lithium has similar properties to potassium

6. calcium has similar properties to magnesium

7. neon has similar properties to xenon

8. Iodine has similar properties to chlorine

5 0
3 years ago
What is the density of a 12-gram sample of zinc with volume of 8.4 cm3? <br><br> pls hurry pls
Sindrei [870]

AnswerIm telling your teacher "Ms.Byrd" your in 8th grade and go to berry middle?

Explanation:

8 0
3 years ago
3.
sineoko [7]

Answer:

3. V = 0.2673 L

4. V = 2.4314 L

5. V = 0.262 L

6. V = 2.224 L

Explanation:

3. assuming ideal gas:

  • PV = RTn

∴ R = 0.082 atm.L/K.mol

∴ V1 = 225 L

∴ T1 = 175 K

∴ P1 = 150 KPa = 1.48038 atm

⇒ n = RT/PV

⇒ n = ((0.082 atm.L/K.mol)(175 K))/((1.48038 atm)(225 L))

⇒ n = 0.043 mol

∴ T2 = 112 K

∴ P2 = P1 = 150 KPa = 1.48038 atm

⇒ V2 = RT2n/P2

⇒ V2 = ((0.082 atm.L/K.mol)(112 K)(0.043 mol))/(1.48038 atm)

⇒ V2 = 0.2673 L

4. gas is heated at a constant pressure

∴ T1 = 180 K

∴ P = 1 atm

∴ V1 = 44.8 L

⇒ n = RT/PV

⇒ n = ((0.082 atm.L/K.mol)(180 K))/((1 atm)(44.8 L))

⇒ n = 0.3295 mol

∴ T2 = 90 K

⇒ V2 = RT2n/P

⇒ V2 = ((0.082 atm.L/K.mol)(90 K)(0.3295 mol))/(1 atm)

⇒ V2 = 2.4314 L

5.  V1 = 200 L

∴ P1 = 50 KPa = 0.4935 atm

∴ T1 = 271 K

⇒ n = RT/PV

⇒ n = ((0.082 atm.L/K.mol)(271 K))/((0.4935 atm)(200 L))

⇒ n = 0.2251 mol

∴ P2 = 100 Kpa = 0.9869 atm

∴ T2 = 14 K

⇒ V2 = RT2n/P2

⇒ V2 = ((0.082 atm.L/K.mol)(14 K)(0.2251 mol))/(0.9869 atm)

⇒ V2 = 0.262 L

6.a)  ∴ V1 = 24.6 L

∴ P1 = 10 atm

∴ T1 = 25°C = 298 K

⇒ n = RT/PV

⇒ n = ((0.082 atm.L/K.mol)(298 K))/((10 atm)(24.6 L))

⇒ n = 0.0993 mol

∴ T2 = 273 K

∴ P2 = 101.3 KPa = 0.9997 atm

⇒ V2 = RT2n/P2

⇒ V2 = ((0.082 atm.L/K.mol)(273 K)(0.0993 mol))/(0.9997 atm)

⇒ V2 = 2.224 L

3 0
3 years ago
1. Marisa determined the melting point of a substance to be 24.5C. Find the percent error of her measurement if the actual melti
USPshnik [31]

Answer:

\%\ Error = 21.5\%

Explanation:

Given

Measured = 24.5

Actual = 31.2

Required

Determine the percentage error

First, we need to determine the difference in the measurement

Difference = |Actual - Measured|

Difference = |31.2 - 24.5|

Difference = |6.7|

Difference = 6.7

The percentage error is calculated as thus:

\%\ Error = \frac{Difference * 100\%}{Actual}

\%\ Error = \frac{6.7 * 100\%}{31.2}

\%\ Error = \frac{670\%}{31.2}

\%\ Error = 21.4743589744\%

\%\ Error = 21.5\% <em>approximated</em>

6 0
3 years ago
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