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Alex787 [66]
2 years ago
5

Which of the following shows the combustion of a hydrocarbon?

Chemistry
1 answer:
arlik [135]2 years ago
7 0

Answer:

C

Explanation:

with combustion you must know that your products must be carbon dioxide and water. I think you copied your question incorrectly.

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xxTIMURxx [149]

Answer:

In an experiment, a student transferred 4.50 mL of a liquid into a pre-weighed beaker (the weight of which was determined to be 35.986 g ).

Explanation:

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6 0
3 years ago
How do the biosphere and geosphere interact? give an example
egoroff_w [7]

Answer:

Plants

Explanation:

Plants, part of the biosphere, grow in the soil, which is part of the geosphere

hope this helped :)

5 0
3 years ago
Why is coke sprinkled on the top of electrolyte in the bayer's process?​
Vesnalui [34]

Powdered coke prevent the heat loss. As a result, it prevents burning of carbon electrodes.

4 0
2 years ago
A(n) has a definite volume but no shape of its own.
tatuchka [14]

Answer:

liquids

Explanation:

8 0
3 years ago
How to do q solution, qrxn, moles of Mg , and delta Hrxn?
Helga [31]

Answer:

<em> 14, 508J/K</em>

ΔHrxn =q/n

where q = heat absorbed and n = moles

Explanation:

<em>m = mass of substance (g) = 0.1184g</em>

1 mole of Mg - 24g

<em>n</em> moles - 0.1184g

<em>n = 0.0049 moles.</em>

Also, q = m × c × ΔT

<em> Heat Capacity, C of MgCl2 = 71.09 J/(mol K)</em>

<em>∴ specific heat c of MgCL2 = 71.09/0.0049 (from the formula c = C/n)</em>

<em>= 14, 508 J/K/kg</em>

ΔT=  (final - initial) temp = 38.3 - 27.2

= 11.1 °C.

mass of MgCl2 = 95.211 × 0.1184 = 11.27

⇒ q = 11.27g × 11.1 °C × <em>14, 508 j/K/kg </em>

<em>= 1,7117.7472 J °C-1 g-1</em>

<em />

<em>∴ ΔHrxn = q/n</em>

<em>=1,7117.7472  ÷ 0.1184 </em>

<em>= 14, 508J/K</em>

6 0
3 years ago
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