Question

In the electrolysis of water, how long will it take to produce 165.0 L of H2 at 1.0 atm and 273 K using an electrolytic cell through which the current is 113.0 mA?

Answer 1

In the electrolysis of water,  3490 hour will it take to produce 165.0 L of H2 at 1.0 atm and 273 K using an electrolytic cell through which the current is 113.0 mA.

What is Ideal Gas Law ?

The ideal gas law states that the pressure of gas is directly proportional to the volume and temperature of the gas.

It is expressed as

PV = nRT

where,

P = Pressure

V = Volume in liters

n = number of moles of gas

R = Ideal gas constant

T = Temperature in kelvin

Here,

P = 1.0 atm

V = 165.0 L

R = 0.0821 atm. L/mol.K (Ideal gas constant)

T = 273 K

n = ?

Now put the value in above expression, we get

PV = nRT

1.0 atm × 165.0 L = n × 0.0821 atm. L/mol.K × 273 K

165.0 atm. L = n × 22.4  atm. L/mol

$n = \frac{165.0\ \text{atm. L}}{22.4\ \text{atm. L/mol}}$

n = 7.36 mol

The reaction is

2H⁺ + 2e⁻ → H₂

1 mol of electrons is produced from 96500 C

So,

$96500 \frac{C}{\text{mol} \times e} \times 2e \times 7.36\ \text{mol}$

= 1,420,480 C

Convert milliampere to C/s

1mA = 0.001 C/s

113.0 mA = 113.0 × 0.001

               = 0.113 c/s

What is relationship between current, charge and time ?

The relation between current, charge and time is expressed as:

$I = \frac{Q}{t}$

where,

I = Current

Q = Charge in Coulomb

t = time

Now put the value in above formula we get

$I = \frac{Q}{t}$

  $= \frac{1,420,480\ C}{0.113\ C/s}$

  = 12,570,619.469 s

  = 3490 hour

Thus from the above conclusion we can say that In the electrolysis of water,  3490 hour will it take to produce 165.0 L of H2 at 1.0 atm and 273 K using an electrolytic cell through which the current is 113.0 mA.

Learn more about the Ideal Gas Law here: brainly.com/question/25290815

#SPJ4