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postnew [5]
1 year ago
14

Water in a metal pot is heated over a campfire. Primarily, by wat means of energy transfer is thermal energy moved from the fire

to the bottom of the pot?
Physics
1 answer:
Art [367]1 year ago
7 0

when water in a metal pot is heated over a campfire. Primarily, by means of convection energy transfer is thermal energy moved from the fire to the bottom of the pot

<h3 /><h3>What is thermal energy?</h3>

It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.

Thermal energy can flow by different means such as conduction, convection, and radiation.

As given in the problem when water in a metal pot is heated over a campfire. The energy we receive around the campfire is mostly due to the effect of the radiation of the heat but the Primary means of energy transfer is thermal energy moved from the fire to the bottom of the pot because of the convection.

Thus, when water is heated in a metal pot over a campfire. Thermal energy is primarily transferred from the fire to the bottom of the pot through convection.

Learn more about thermal energy from here

brainly.com/question/3022807

#SPJ1

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A mass of .1539 kg moves down a 5 meter ramp in 2 seconds. What
enot [183]

Answer:

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3 years ago
This diagram shows particles that make up an atom. Which label BEST completes the diagram ?
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8 0
4 years ago
What is the frequency of a wave having a period equal to 18 seconds <br>​
Ivanshal [37]

Explanation:

The time taken by a wave crest to travel a distance equal to the length of wave is known as wave period.

The relation between wave period and frequency is as follows.

T = \frac{1}{f}T=

f

1

where, T = time period

f = frequency

It is given that wave period is 18 seconds. Therefore, calculate the wave period as follows.

T = \frac{1}{f}T=

f

1

or, f = \frac{1}{T}f=

T

1

= \frac{1}{18 sec}

18sec

1

= 0.055 per second (1cycle per second = 1 Hertz)

or, f = 5.5 \times 10^{-2} hertz5.5×10 −2 hertz

<h3>Thus, we can conclude that the frequency of the wave is 5.5 \times 10^{-2} hertz5.5×10 −2 hertz .</h3>
3 0
3 years ago
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