The average atomic mass of the hypothetical element is the sum of the products of the isotopes and their percentage abundance. For this given,
atm = (84.95 amu)(0.371) + (86.95 amu)(0.629)
= 86.208 amu
Thus, the average atomic mass of the element is 86.208 amu.
Answer:
the second statement,the third&the fifth
Answer:
The reaction can produce 287 grams of iron(II) carbonate
Explanation:
To solve this question we must find the moles of iron(II) chloride that react. Using the chemical equation we can find the moles of iron(II) carbonate and its mass -Molar mass FeCO3: 115.854g/mol-
<em>Moles FeCl2:</em>
1.24L * (2.00mol / L) = 2.48 moles FeCl2
As 1 mol FeCl2 produce 1 mol FeCO3, the moles of FeCO3 = 2.48 moles
<em>Mass FeCO3:</em>
2.48mol * (115.854g / mol) =
<h3>The reaction can produce 287 grams of iron(II) carbonate</h3>
Answer:
Frequency = 0.8×10¹⁵ Hz
Explanation:
Given data:
Frequency of photon = ?
Wavelength of photon = 3.75 ×10⁻⁷ m
Solution:
Formula:
Speed of photon = wavelength × frequency
Frequency = speed of photon / wavelength
Now we will put the values in formula.
Frequency = 3 ×10⁸ m/s / 3.75 ×10⁻⁷ m
Frequency = 0.8×10¹⁵ s⁻¹
s⁻¹ = Hz
Frequency = 0.8×10¹⁵ Hz
