Question

two small charged objects repel each other with a force 2.53 when separated by a distance 0.11. if the charge on each object is reduced to 67.9% of its original value and the distance between them is reduced to 0.053 the force becomes

Answer 1

The force between the charges will be 10.9 N.

What is the electrostatic force?

The electrostatic attraction particles that make up the electrostatic force behave as both an attracting and a repulsive force. The force is inversely proportional to the square of the distance between them.

F ∝ 1 / r²

F = k / r²

Fr² = k

When two tiny charged objects are 0.11 of a distance apart, they repel one another with a force of 2.53. If the distance between the two particles is cut to 0.053 and the charge on each item is decreased to 67.9% of its initial amount. Then the force will be

F₁r₁² = F₂r₂²

2.53 × (0.11)² = F × (0.053)²

F = 10.9 N

More about the electrostatic force link is given below.

brainly.com/question/9774180

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