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Verdich [7]
2 years ago
15

Whats 47,000 resistance converted to kilo or mega ohms.

Engineering
1 answer:
Julli [10]2 years ago
7 0
  1. The conversion of 47,000 Ohms to kilo-ohms is equal to 47 kilo-ohms.
  2. The conversion of 47,000 Ohms to mega-ohms is equal to 0.047 kilo-ohms.

<h3>What is resistance?</h3>

Resistance can be defined as an opposition to the flow of current in an electric circuit. Also, the standard unit of measurement of the resistance of an electric component is Ohms, which can be converted to kilo-ohms or mega-ohms.

For Ohms to kilo-ohms, we have:

1 Ohms = 0.001 kilo-ohms

47,000 Ohms = X kilo-ohms

Cross-multiplying, we have:

X = 0.001 × 47000

X = 47 kilo-ohms.

For Ohms to mega-ohms, we have:

1,000,000 ohms = 1 mega-ohms

47,000 Ohms = X mega-ohms

Cross-multiplying, we have:

X1,000,000 = 47,000

X = 47,000/1,000,000

X = 0.047 kilo-ohms.

Read more resistance here: brainly.com/question/19582164

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Answer:

Q=127.66W

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Explanation:

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To solve any problem related to heat transfer, the general equation is used

Q = delta / R

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R=\frac{6(0.0001)}{(1.25)(0.026)} +\frac{5(0.012)}{(1.25)(0.026)}+\frac{1}{(25)(1.25)} =0.235 K/w

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part b

we use the same ecuation with Q=127.66

Q = delta / R

ΔR=\frac{L}{KA} +\frac{1}{hA} \\R=\frac{L}{(0.035)(1.25)} +\frac{1}{(25)(1.25)}\\ R=22.85L+0.032\\Q=(T1-T2)/R\\\\127.66=(25-(-5))/(22.85L+0.032)\\solving for L\\L=9.2mm

6 0
3 years ago
What is a thermal reservoir?
Mekhanik [1.2K]

Answer:

Explanation:

Thermal reservoir:

   It is the body which have infinite amount of heat capacity and store large amount of heat.The temperature of thermal reservoir is constant and does not change with time.The temperature of thermal reservoir is not change even heat is going out from reservoir or heat going inside the reservoir.The temperature of thermal reservoir remains constant and does not depend on the surroundings.

7 0
4 years ago
A plate clutch is used to connect a motor shaft running at 1500rpm to shaft 1. The motor is rated at 4 hp. Using a service facto
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Answer:

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Explanation:

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now,

KW=\frac{2\pi n M_t}{60 \times 10^6} \\2.9828=\frac{2\pi \times 1500 M_t}{60 \times 10^6}\\M_t=\frac{2.9828\times 60 \times 10^6}{2\pi \times 1500 }

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Explanation:

hope this helps

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