Answer:
Distribution factor P = =38.33
V = 7.826 ml
Explanation:
given details:
BOD =230 mg/l
DO inital = 8.0mg/l
DO final = 2.0mg/l
we know
BOD = [DO inital -DO final] * distribution factor
230 = [8 - 2] D.F
Distribution factor P 
Distribution factor P = =38.33
THE RANGE OF WASTE WATER VOLUME IN 300 ml bottle is
distribution factor 

V = 7.826 ml
Answer:
The molecular weight will be "28.12 g/mol".
Explanation:
The given values are:
Pressure,
P = 10 atm
= 
=
Temperature,
T = 298 K
Mass,
m = 11.5 Kg
Volume,
V = 1000 r
= 
R = 8.3145 J/mol K
Now,
By using the ideal gas law, we get
⇒ 
o,
⇒ 
By substituting the values, we get


As we know,
⇒ 
or,
⇒


Answer:
Heat flux of CO₂ in cgs
= 170.86 x 10⁻⁹ mol / cm²s
SI units
170.86 x 10⁻⁸ kmol/m²s
Explanation:
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Therefore, the Option A is correct.
Read more about career advancement
<em>brainly.com/question/7053706</em>
Answer:
The answer is "2 m/s".
Explanation:
The triangle from of the right angle:

Differentiating the above equation:


