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sertanlavr [38]
1 year ago
8

A chef needs 20 walnuts for a recipe and has to crack each one. the effort force is 4.1inches from the fulcrum and the walnut si

ts 2.2inces from the fulcrum. if the chef can only apply 7lb of force, what is the maximum amount of resistance force the walnut can apply in order for the nut to be cracked? answer should be to the nearest (0.0)
Engineering
1 answer:
Colt1911 [192]1 year ago
3 0

The calculated answer is 4 kgf. The greatest resisting force that the walnut may exert before the nut cracks

In physics, resistive force is a a type of force, or the vector sum of the various forces, whose direction is opposite to the motion of a body, and may refer to: Friction, during sliding and/or rolling. During moving through a fluid, drag (physics) (see fluid dynamics). For all compression positions, the direction of specific deformation as a function of shell thickness and geometric mean diameter was identical to the direction of energy.

If load is 40 kgf and effort is?

effort arm=20 cm, load arm=2 cm

By the moments' principle,

effort arm equals load arm.

40kgf×2cm=E×10cm

∴E=40×220kgf=4kgf.

Learn more about Effort here-

brainly.com/question/9457233

#SPJ4

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Explanation:

Complete question

A triangular plate with a base 5 ft and altitude 3 ft is submerged vertically in water  so that the top is 4 ft below the surface. If the base is in the surface of water, find the force against onr side of the plate. Express the hydrostatic force against one side of the plate as an integral and evaluate it. (Recall that the weight density of water is 62.5 lb/ft3.)

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