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crimeas [40]
3 years ago
11

If you drop a 50 gram piece of metal that has a temperature of 110°Celsius into 1000 grams of water at 25°Celsius, what best des

cribes what would occur?
A.) The water will quickly reach the boiling point.
B.) The water’s temperature will stay the same, but the metal will cool down.
C.) The water’s temperature will increase, and the metal will stay constant.
D.)The water and the metal’s temperature will reach the same temperature.
Physics
2 answers:
zaharov [31]3 years ago
8 0

Answer:

D.)The water and the metal’s temperature will reach the same temperature.

Explanation:

As we know that heat is a dynamic energy which will flow from high temperature to low temperature.

So here we know that 50 g metal piece at 110 degree Celsius is dropped into the water at 25 degree Celsius. Since metal is at higher temperature so here the heat will flow from metal to the water and this will continue till the temperature of these two bodies will become equal.

So here the final temperature of metal and the water will be same at thermal equilibrium.

So here correct answer will be

D.)The water and the metal’s temperature will reach the same temperature.

LuckyWell [14K]3 years ago
7 0
If you drop a 50 gram piece of metal that has a temperature of 110°Celsius into 1000 grams of water at 25°Celsius, <span>D.)The water and the metal’s temperature will reach the same temperature. In any system undergoing heat transfer, the objects involved will eventually reach the same temperature, signifying thermal equilibrium.</span>
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2560 meters in 60 seconds, what is his average speed (velocity)
jok3333 [9.3K]
42.6 is the answer I believe because you would do 2,560 divided by 60 if I'm correct.
5 0
3 years ago
A transformer has a secondary voltage of 140 volts and a secondary current of 3.5 amps. if the primary current is 10 amps, what
Lynna [10]

For an ideal transformer power loss is assumed to be zero

i.e. the power in primary coil due to input voltage must be equal to power in secondary coil due to output voltage

this can be written in form of equation

V_1 i_1 = V_2 i_2

here we know that

V_2 = 140 volts

i_2 = 3.5 A

i_1 = 10 A{/tex]now we will use above equation[tex]140*3.5 = 10 * V_1

V_1 = 49 volts

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3 years ago
The relationship between mass and inertia is described by newton's second law of motion. true or false
Mariana [72]
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4 0
3 years ago
Find the length (in m) of an organ pipe closed at one end that produces a fundamental frequency of 494 Hz when air temperature i
elena-14-01-66 [18.8K]

Answer:

0.173 m.

Explanation:

The fundamental frequency of a closed pipe is given as

fc = v/4l .................. Equation 1

Where fc = fundamental frequency of a closed pipe, v = speed of sound  l = length of the pipe.

Making l the subject of the equation,

l = v/4fc ................ Equation 2

also

v = 331.5×0.6T ................. Equation 3

Where T = temperature in °C, T = 18.0 °c

Substitute into equation 3

v = 331.5+0.6(18)

v = 331.5+10.8

v = 342.3 m/s.

Also given: fc = 494 Hz,

Substitute into equation 2

l = 342.3/(4×494)

l = 342.3/1976

l =0.173 m.

Hence the length of the organ pipe = 0.173 m.

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3 years ago
As speed (velocity) increases, potential energy increases true or false
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Answer:

true

Explanation:

3 0
3 years ago
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