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Marrrta [24]
1 year ago
6

2. Testing Encryption Validity Encryption is the process of converting information algorithmically so that only a valid recipien

t can read the information before the end of its validity period. For a each encrypted message, we are given: • the instruction Count, i.e., the number of keys that a hijacker can test per second in order to trwand crack the code Solve question 1 riod • a list of keys that can tested by the hijacker Leveraging this information, our goal is to determine if the hijacker can crack the code within its validity period. Each test will need return two items: 1. If the hijacker cracks the code within its validity period (1 if true, o if false) 2. The strength of the encryption (cf. further below to read about the definition of strength) The strength of the encryption is the number of keys that must be tested to break the encryption. It is defined as the product: dmax * 105, where dmax is the maximum number of divisors possible within the set of keys: • keys is a list of positive integers, keys[i], that act as keys. • the number of divisors (or divisibility) of an element is the number of elements in the set keys that are greater than 1 and are divisors of the element, i.e. element modulo divisor=0. • the element m that has the maximum number of divisors in keys determines dmax Notes: • Any divisor of a key must be greater than 1. • The list may contain duplicates - e.g., if keys = [2, 4,4), the strength is 3 * 105, as 4 can be divided by 2 and 4 respectively, so 4 has 3 divisors in the list of keys. Example: • instructionCount = 1000 • validityPeriod = 10000 • keys = [2, 4, 8, 2] Looking at the elements in keys, in order of appearance: • 2 is divisible by [2, 2] so its degree of divisibility is 2 • 4 is divisible by [2, 4,2] so its degree of divisibility is 3 • 8 is divisible by [2, 4, 8, 2] so its degree of divisibility is 4 • 2 is divisible by [2.2] so its degree of divisibility is 2, as in the first case The element m that has the maximum number of divisors is 8 and its degree of divisibility is 4. The encryption strength is 4 * 105 = 400,000. In this example, the hijacker can test 1000 keys per second (instruction Count) and the encrypted message has a validity period of 10 000 seconds (validityPeriod), which means that the hijacker can test 1000 * 10 000 = 10% keys while the message is still valid. This is greater than the encryption strength, so the hijacker can expect to crack the code. The expected array is hence [1, 400000] because the hijacker can decrypt the message in time, and the strength of the encryption is 400000 Function Description Complete the function encryptionValidity in the editor below. encryptionValidity has the following parameters: • int instruction Count: an integer, the number of keys the hijacker can test per second • int validityPeriod: an integer, the number of seconds the message must be protected int keys[n]: an array of integers, keys for encryption/decryption Returns: • List [int, int]: 2 element integer array result containing the expected outputs described above. Constraints • 13 instruction Count validityPeriods 108 1sns 105
Engineering
1 answer:
4vir4ik [10]1 year ago
7 0

OLAP (online analytical processing) software is the software to perform various high-speed analytics of large amounts of data from a data center, data mart, or other integrated, centralized data store.

<h3>What is the use of Online Analytical Processing (OLAP)?</h3>

OLAP provides pre-calculated data for various data mining tools, business modeling tools, performance analysis tools, and reporting tools.

OLAP can help with Planning and Budgeting andFinancial Modeling. Online Analytical Processing (OLAP) is included in many Business Intelligence (BI) software applications. It is used for a range of analytical calculations and other activities.

Therefore, OLAP (online analytical processing) software is the software to perform various high-speed analytics of large amounts of data from a data center, data mart, or other integrated, centralized data store.

Learn more about Online Analytical Processing (OLAP):

brainly.com/question/13286981

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\dfrac{P_1}{\gamma}+\dfrac{v_1^2}{2g} = \dfrac{P_2}{\gamma}+\dfrac{v_2^2}{2g}\\\dfrac{P_1-P_2}{\gamma}=\dfrac{v_2^2-v_1^2}{2g}\\\dfrac{-40\times 10^3\times 2}{900}=v_2^2-v_1^2

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