an insulating sphere with a radius of 20 cm carries a uniform volume charge density of 1.5 x 10-6 c/m3. find the magnitude of th
1 answer:
The magnitude of the electric field at a point inside the sphere that lies 8.0 cm from the center is 4.5 ×
Given
Radius = 20 cm
Electric field at a point inside the sphere that lies 8.0 cm from the center.
ρ = 1.5 x 10-6 c/m3
E (r) = ρr / 3εο = 1.5 × × 8 ×
/ 3 × 8.85 ×
= 4.5 ×
The physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them, is known as an electric field (also referred to as an E-field[1]). [2] It also describes the physical field of a system of charged particles. [3] Electric charges and time-varying electric currents are the basis of electric fields. A manifestation of the electromagnetic field, one of the four fundamental interactions (sometimes known as forces) of nature, is electromagnetic fields, which also include electric and magnetic fields.
Electric fields play a significant role in many branches of physics and are used in electrical engineering. For instance, in atomic physics and chemistry, the electric field acts as the attracting force that holds the atomic nucleus and electrons together in atoms. Additionally, it is the driving force for atoms' chemical bonds.
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Answer:
t = 5.59x10⁴ y
Explanation:
To calculate the time for the ¹⁴C drops to 1.02 decays/h, we need to use the next equation:
(1)
<em>where : is the number of decays with time, A₀: is the initial activity, λ: is the decay constant and t: is the time.</em>
To find A₀ we can use the following equation:
(2)
<em>where N₀: is the initial number of particles of ¹⁴C in the 1.03g of the trees carbon </em>
From equation (2), the N₀ of the ¹⁴C in the trees carbon can be calculated as follows:
<em>where : is the tree's carbon mass,
: is the Avogadro's number and
: is the ¹²C mass. </em>
Similarly, from equation (2) λ is:
<em>where t 1/2: is the half-life of ¹⁴C= 5700 years </em>
So, the initial activity A₀ is:
Finally, we can calculate the time from equation (1):
I hope it helps you!