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sweet-ann [11.9K]
1 year ago
5

an insulating sphere with a radius of 20 cm carries a uniform volume charge density of 1.5 x 10-6 c/m3. find the magnitude of th

e electric field at a point inside the sphere that lies 8.0 cm from the center.
Physics
1 answer:
adelina 88 [10]1 year ago
4 0

The magnitude of the electric field at a point inside the sphere that lies 8.0 cm from the center is  4.5 × 10^{3}

Given

Radius = 20 cm

Electric field at a point inside the sphere that lies 8.0 cm from the center.

ρ =  1.5 x 10-6 c/m3

E (r) = ρr / 3εο = 1.5 × 10^{-6} × 8 × 10^{-2}/ 3 × 8.85 × 10^{-12}  = 4.5 × 10^{3}

The physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them, is known as an electric field (also referred to as an E-field[1]). [2] It also describes the physical field of a system of charged particles. [3] Electric charges and time-varying electric currents are the basis of electric fields. A manifestation of the electromagnetic field, one of the four fundamental interactions (sometimes known as forces) of nature, is electromagnetic fields, which also include electric and magnetic fields.

Electric fields play a significant role in many branches of physics and are used in electrical engineering. For instance, in atomic physics and chemistry, the electric field acts as the attracting force that holds the atomic nucleus and electrons together in atoms. Additionally, it is the driving force for atoms' chemical bonds.

Learn more about electric field here:

brainly.com/question/15800304

#SPJ4

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Please help ! Which of the following objects has the greatest momentum?
shusha [124]

Answer:

maybe the third one....

8 0
2 years ago
A car is behind a truck going 25 m/s on the highway. The car’s driver looks for an opportunity to pass, guessing that his car ca
user100 [1]

Answer:

No he should not attempt the pass

Explanation:

Let t be the time it takes for the car to pass the truck. The driver should ONLY attempt to pass when the distance covered by himself plus the distance covered by the oncoming car is less than or equal 400 m (a near miss)

At acceleration of 1m/s2 and a clear distance of 10 + 20 + 10 = 40 m, we can use the following equation of motion to estimate the time t in seconds

s = at^2/2

40 = 1t^2/2

t^2 = 80

t = \sqrt{80} = 8.94 s

Within this time frame, the first car would have traveled a total distance of the clear distance (40m) plus the distance run by the truck, which is

8.94 * 25 = 223.6m

So the total distance traveled by the first car is 223.6 + 40 = 263.6m

The distance traveled by the 2nd car within 8.94 s at rate of 25m/s is

8.94 * 25 = 223.6 m

So the total distance covered by both cars within this time frame

223.6 + 263.6 = 487.2m > 400 m

So no, he should not attempt the pass as we will not clear it in time.

8 0
3 years ago
A current of 0.001 A can be felt by the human body. 0.005 A can produce a pain response. 0.015 A can cause a loss of muscle cont
lys-0071 [83]

Answer:

In summary, it is safe to handle this voltage with dry hands because the current value that you pass through the body is smaller than its underestimated sensitivity.

Explanation:

The current flowing through your system is described by Ohm's law

        V = I R

where I is the current, V the voltage and R the resistance

in this case three barateras are taken in series giving a total voltage of V = 4.5 V the typical resistance values ​​of dry skin is R = 1000 000Ohm and the resinification of wet skin is R = 100000 ohm

let's calculate the current flowing

        I = V / R

        I = 4.5 / 1000000

        I = 4.5 10⁻⁶ A

this is the current with dry hands, we see that much less than the value that allows to feel a painful response by the body

If the skin is

         I = 4,5 / 100,000

         I = 4.5 10⁻⁵ A

This value is small, but it is close to the pain threshold, but it is in the range of slight discomfort.

In summary, it is safe to handle this voltage with dry hands because the current value that you pass through the body is smaller than its underestimated sensitivity.

7 0
2 years ago
GIVING BRAINLIEST PLEASE HELP!!
Marrrta [24]
The answer is D hope it helps
8 0
3 years ago
An 81.5-kg man stands on a horizontal surface.
OLga [1]

Answer:

a)V= 0.0827 m³

b)P=181.11 x 10²  N/m²

Explanation:

Given that

m = 81.5 kg

Density ,ρ = 985 kg/m³

As we know that

Mass = Volume x Density

81.5 = V x 985

V= 0.0827 m³

The force exerted by weight = m g

 F= m g= 81.5 x 10 = 815 N      ( Take ,g= 10 m/s²)

Area ,A= 4.5 x 10⁻² m²

The Pressure P

P=\dfrac{F}{A}

P = \dfrac{815}{4.5\times 10^{-2}}\ N/m^2

P=181.11 x 10²  N/m²

7 0
3 years ago
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