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KiRa [710]
2 years ago
14

How does the value of gravitational

Physics
1 answer:
tester [92]2 years ago
4 0

Explanation:

according to my understanding, the value of gravitational acceleration changes because;different planets have different gravitational pull.

for example you may ask yourself why is it that the gravitational acceleration is not the same on earth and the moon.

this is because the gravitational force acting on an object on earth is greater than the gravitational force acting on an object and the Moon .

You know the moon is located in the space and one can fly, stand,dance etc.

all because the gravitational acceleration is low.

as for me when the distance from the centre of the Earth increases,

the gravitational acceleration decreases.

A good example is given by the moon.

The moon is miles away from the Earth and its gravitational acceleration is quite low .hope you got me.

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Who discovered the laws of physics
astra-53 [7]

Answer: Isaac Newton

Explanation: Isaac Newton is popularly remembered as the man who saw an apple fall from a tree, and was inspired to invent the theory of gravity. If you have grappled with elementary physics then you know that he invented calculus and the three laws of motion upon which all of mechanics is based.

6 0
3 years ago
A scientist begins with 100 milligrams of a radioactive substance that decays exponentially. After 33 hours, 50 mg of the substa
Hoochie [10]

Answer:

m\approx34.99

Explanation:

Radioactive decay behaves according to the law of exponential decay:

m(t)=m_0*e^{-rt}

Where:

r=Decay\hspace{3}rate

t=Time(In\hspace{3}days)

m_0=Initial\hspace{3}amount\hspace{3}of\hspace{3}substance

m(t)=Amount\hspace{3}of\hspace{3}substance\hspace{3}at\hspace{3}time\hspace{3}t

So we need to find the decay rate r. Let's find it using the equation and the data provide, but first, we need to convert the hours in days:

50h*\frac{1day}{24h}=\frac{25}{12}day\\  33h*\frac{1day}{24h} =\frac{11}{8}day

Now for t=\frac{11}{8},m=50 then:

m(\frac{11}{8} )=100*e^{-r(\frac{11}{8}) } =50

Divide both sides by 100:

e^{-r(\frac{11}{8}) } =\frac{1}{2}

Take the natural logarithm of both sides:

-\frac{11}{8}x=ln(\frac{1}{2} )

Multiply both sides by -8/11:

x=\frac{-8ln(\frac{1}{2} )}{11} \approx0.504107

Now we have found the rate decay r, let's find how many milligrams will remain after 59 hours (25/12 day):

m(\frac{25}{12} )=100*e^{-0.504107*\frac{25}{12}) } =100*e^{-1.050222917}=34.98597508\approx35.99

4 0
3 years ago
The measure of an object's mass and velocity is called __________.
tamaranim1 [39]

By definition, we have to:

p = m * v

Where,

p: linear momentum

m: mass of the object

v: object speed

Therefore, knowing the mass of an object and its speed, we have the linear momemtum of the object.

In general, it is useful to calculate the momentum of objects in conservation problems to find the velocity before or after the collision of two objects.

Answer:

The measure of an object's mass and velocity is called momentum.

d. momentum

7 0
4 years ago
Read 2 more answers
What best illustrates that light behaves like particles
Ira Lisetskai [31]
The light particle<span> conceived by Einstein is called a photon. The main point of his </span>light<span> quantum theory is the idea that </span>light's energy is related to its oscillation frequency. <span>Einstein believed </span>light<span> is a </span>particle<span> (photon) and the flow of photons is a </span>wave<span>.</span>
3 0
3 years ago
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Experiment 1: A study is done to determine which of two fuel mixtures allows a rocket to travel farther over a period of time. R
leva [86]

Answer: D

Experiment 1 has a confounding variable related to the mass of the rockets. Any variation in mass may cause a discrepancy in the distance traveled.

This is the answer to the question because:

  • Both experiments do have a confounding variable.
  • Experiment 1 doesn't have to stay constant.
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  • High blood pressure people will not make the results confusing.

The answer has to be the option D. Hope this helps you!

3 0
4 years ago
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