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stepan [7]
3 years ago
6

What is common to all of the oxidation reactions in the krebs cycle?

Chemistry
1 answer:
jek_recluse [69]3 years ago
6 0
<span>They are all characterized by a loss of electrons from an organic molecule coupled to the reduction of an electron acceptor.</span>
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What mass of O2, in grams, is required to completely react with 0.025 g C3H8?
8090 [49]
2C3H8+ 702--->6CO2+8H20
FROM  Equation  above  2  moles of C3H8    reacted with  7  moles  of oxygen  to  form   6  moles of  c02 plus  8  molesof  H2O  
the  moles  of  c3H8  reacted is = MASS/ R.F.M
THE  R.F.M =48+8=44
Number  of  moles is  hence 0.025/44=5.68x10^-4
 
since  ratio  of  C3H8  to   O2 is  2:7  Therefore moles of   O2  reacted  is  1.989 x10^-3
mass= r.f.m  x  number  of  moles
(1.989x10^-3)   x  32 =0.064g
6 0
3 years ago
A car reaches 80 km/hr, then suddenly crashed into a concrete wall. Without a seat
Debora [2.8K]

Answer:

C

Explanation:

inertia

inertia is the reluctance of an object at rest or moving to change its state of rest or motion

because the car was moving, the dummy moves with the speed of the car..so when the crash happened the dummy continued to move..it was feeling reluctant to come to rest so was moving

4 0
3 years ago
The half life of a new isotope found on Mars is 2 years. It takes 10 years to get the sample back to Earth. If the astronauts st
yawa3891 [41]

Answer:

3.99 g

Explanation:

The following data were obtained from the question:

Half life (t½) = 2 years.

Original amount (N₀) = 128 g

Time (t) = 10 years

Amount remaining (N) =..?

Next, we shall determine the rate of disintegration of the isotope. This can be obtained as follow:

Half life (t½) = 2 years.

Decay constant (K) =.?

K= 0.693/t½

K = 0.693/2

K = 0.3465 year¯¹.

Finally, we shall determine the amount remaining after 10 years i.e the amount remaining when they arrive on Earth. This can be obtained as follow:

Original amount (N₀) = 128 g

Time (t) = 10 years

Decay constant (K) = 0.3465 year¯¹.

Amount remaining (N) =..?

Log (N₀/N) = kt/2.3

Log (128/N) = (0.3465 × 10)/2.3

Log (128/N) = 1.5065

Take the antilog of 1.5065

128/N = Antilog (1.5065)

128/N = 32.1

Cross multiply

128 = 32.1 × N

Divide both side by 32.1

N = 128/32.1

N = 3.99 g

Therefore, the amount remaining is 3.99 g

3 0
3 years ago
H3PO4 what’s the name?
jasenka [17]

Answer:

Phosphoric acid

Explanation:

8 0
2 years ago
Read 2 more answers
Which of the following best defines an acid
erica [24]
An acid is a hydrogen containing substance with a PH between 1-7 and is capable of donating a proton (hydrogen ion)
7 0
3 years ago
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