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gogolik [260]
3 years ago
6

Suppose that a molecule has four bonding groups and one lone pair on the central atom. Suppose further that the molecule is conf

ined to two dimensions. (This is a purely hypothetical assumption for the sake of understanding the principles behind VSEPR theory.) Estimate the bond angles between electron groups.
Chemistry
1 answer:
Grace [21]3 years ago
3 0

Answer:

The bond angles between the axial bonding groups are slightly less than 180°.

The bond angles between the equatorial bonding groups are slightly less than 120°.

Explanation:

Accordign to VSEPR theory, a molecule with four bonding groups and one lone pair on the central atom has a trigonal bipyramidal electronic geometry.

The position of the lone pair can be located in the equatorial position or axial position.

When the lone pair is found in equatorial position, it has two axial groups that repel it and the angle of the lone pair between each axial group is 90°.

When the lone pair is in axial position it has 3 equatorial groups that repel it and the angle of the lone pair between each equatorial group is 90°.

Since the molecule has a lone pair, the most stable geometric structure is when the lone pair is in the equatorial position, because it has fewer repulsions than in the axial position.

The molecular geometry is "seesaw"

The bond angles between the axial bonding groups are slightly less than 180°.

The bond angles between the equatorial bonding groups are slightly less than 120°.

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yaroslaw [1]

Answer:

Density, d = 1.779 g/cm³

Explanation:

The density of a material is given by its mass per unit volume.

Here, height of a piece of magnesium cylinder, h = 5.62 cm

Its diameter, d = 1.34 cm

Radius = 0.67 cm

Volume of he cylinder,

V=\pi r^2 h\\\\\text{Putting the value of r and h, we get :}\\\\V=(\pi \times (0.67)^2\times 5.62)\ cm^3

d=\dfrac{m}{V}\\\\d=\dfrac{14.1\ g}{(\pi \times (0.67)^2\times 5.62)\ cm^3}\\\\d=1.779\ g/cm^3

So, the density of the sample is 1.779 g/cm³.

4 0
3 years ago
sample of atmospheric gas collected at an industrial site is stored in a 250 mL amber glass bottle that has a pressure of 1.02 a
Nady [450]

Answer:- New pressure is 0.942 atm.

Solution:- The volume of the glass bottle would remain constant here and the pressure will change with the temperature.

Pressure is directly proportional to the kelvin temperature. The equation used here is:

P_1T_2=P_2T_1

Where, T_1 and T_2 are initial and final temperatures, P_1 and P_2 are initial and final pressures.

T_1 = 20.3 + 273.15 = 293.45 K

T_2 = -2.0 + 273.15 = 271.15 K

P_1 = 1.02 atm

T_2  = ?

Let's plug in the values in the equation and solve it for final pressure.

1.02atm(271.15K)=P_2(293.45K)

P_2=\frac{1.02atm*271.15K}{293.45K}

P_2 = 0.942 atm

So, the new pressure of the jar is 0.942 atm.


5 0
3 years ago
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OlgaM077 [116]

Answer:

HI(aq) + H₂O(ℓ) ⟶ H₃O⁺(aq) + I⁻(aq)

Explanation:

The HI donates a proton to the water, converting it to a hydronium ion

HI(aq) + H₂O(ℓ) ⟶ H₃O⁺(aq) + I⁻(aq)

Thus, the HI is behaving like a Brønsted acid.

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