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gogolik [260]
3 years ago
6

Suppose that a molecule has four bonding groups and one lone pair on the central atom. Suppose further that the molecule is conf

ined to two dimensions. (This is a purely hypothetical assumption for the sake of understanding the principles behind VSEPR theory.) Estimate the bond angles between electron groups.
Chemistry
1 answer:
Grace [21]3 years ago
3 0

Answer:

The bond angles between the axial bonding groups are slightly less than 180°.

The bond angles between the equatorial bonding groups are slightly less than 120°.

Explanation:

Accordign to VSEPR theory, a molecule with four bonding groups and one lone pair on the central atom has a trigonal bipyramidal electronic geometry.

The position of the lone pair can be located in the equatorial position or axial position.

When the lone pair is found in equatorial position, it has two axial groups that repel it and the angle of the lone pair between each axial group is 90°.

When the lone pair is in axial position it has 3 equatorial groups that repel it and the angle of the lone pair between each equatorial group is 90°.

Since the molecule has a lone pair, the most stable geometric structure is when the lone pair is in the equatorial position, because it has fewer repulsions than in the axial position.

The molecular geometry is "seesaw"

The bond angles between the axial bonding groups are slightly less than 180°.

The bond angles between the equatorial bonding groups are slightly less than 120°.

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Nonamiya [84]

885.39 is the answer you are looking for.

7 0
3 years ago
How many grams of phosphorus are in a sample containing 10^30 phosphorus atoms?
san4es73 [151]

Answer:

18.1 g

 

Explanation:

You know that the atomic weight of phosphorus is equal to  

30.794 u

, where  

u

represent the unified atomic mass unit.

The unified atomic mass unit is equivalent to  

1 g/mol

, but let's take the long road and prove that identity.

Now, the unified atomic mass unit is defined as  

1

12

th

of the mass of a single unbound carbon-12 atom in its ground state and is equivalent to

1 u

=

1.660539

⋅

10

−

24

g

This means that the mass of one phosphorus atom will be

30.974

u

⋅

1.660539

⋅

10

−

24

g

1

u

=

5.14335

⋅

10

−

23

g

You know that one mole of any element contains exactly  

6.022

⋅

10

23

atoms of that element - this is known as Avogadro's number.

Well, if you know the mass of one phosphorus atom, you can use Avogadro's nubmer to determine what the mass of one mole of phosphorus atoms

5.14335

⋅

10

−

23

g

atom

⋅

6.022

⋅

10

23

atoms

1 mole

=

30.974 g/mol

Finally, if one mole of phosphorus atoms has a mass of  

30.974 g

, then  

0.585

moles will have a mass of

0.585

moles

⋅

30.974 g

1

mole

=

18.1 g

From: https://socratic.org/questions/the-atomic-weight-of-phosphorus-is-30-974-u-what-is-the-mass-of-a-phosphorus-sam

3 0
3 years ago
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il63 [147K]

Answer:

I believe the answer is B

Explanation:

to be honest i'm not completely sure, sorry

4 0
3 years ago
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Lostsunrise [7]

Answer:

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Explanation:

6 0
3 years ago
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Zepler [3.9K]

Answer:

Explanation:

Well, obviously a molecule with polar bonds can be polar in itself. It's like saying I am an atheltic person who can just reach the basketball rim with my head and also I can dunk.

But if the question is how can a molecule that in non-polar have polar bonds, well, its because the polar bonds' dipole cancels each other out. It's like a tight rope. If a person pulls in one direction, it intuitively, the rope would go in that direction. However, if a person pulls in the other direction with the same amount of force, the rope stays still. This is the same case. Although molecules can have different electronegativities, the pull of electrons in one direction is cancelled out by a pull in the opposite direction, making the net dipole 0.

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