Question

Calculate the energy, in electron volts, of a photon whose frequency is the following.

Answer 1

Answer:

(a) $E=2.42eV$

(b) $E=1.45*10^{-5}eV$

(c) $E=1.66*10^{-7}eV$

Explanation:

The Planck-Einstein relation allows us to know the energy (E) of a photon, knowing its frequency (f). According to this relation, the energy of the photon is defined as:

$E=hf$

Here h is the Planck constant.

(a)

$E=(4.14*10^{-15}eV\cdot s)(585*10^{12}Hz)\\E=2.42eV$

(b)

$E=(4.14*10^{-15}eV\cdot s)(3.50*10^{9}Hz)\\E=1.45*10^{-5}eV$

(c)

$E=(4.14*10^{-15}eV\cdot s)(40.0*10^{6}Hz)\\E=1.66*10^{-7}eV$