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podryga [215]
3 years ago
13

Show that for a projectile d2 (v2) / dt2 = 2g2

Physics
1 answer:
stich3 [128]3 years ago
8 0
<span>Ok, you need to derive it. Derive v^2</span>
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From the gravity acceleration theorem due to a celestial body or planet, we have that the Force is given as

F = \frac {GMm} {r ^ 2}

Where,

F = Strength

G = Universal acceleration constant

M = Mass of the planet

m = body mass

r = Distance between centers of gravity

The acceleration by gravity would be given under the relationship

g = \frac {F} {m}

g = \frac {GM} {r ^ 2}

Here the acceleration is independent of the mass of the body m. This is because the force itself depended on the mass of the object.

On the other hand, the acceleration of Newton's second law states that

a = \frac {F} {m}

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A 0.1 kg toy contains a compressed spring. when the spring is released the toy fly 0.45 m upwards from ground level before falli
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The speed of the toy when it hits the ground is 2.97 m/s.

The given parameters;

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The speed of the toy before it hits the ground will be maximum. Apply the principle of conservation of mechanical energy to determine the maximum speed of the toy.

P.E = K.E

mgh_{max} = \frac{1}{2} mv_{max}^2\\\\gh_{max} = \frac{1}{2} v_{max}^2\\\\v_{max}^2= 2gh_{max}\\\\v_{max} = \sqrt{2gh_{max}}

Substitute the given values and solve the speed;

v_{max} = \sqrt{2\times 9.8 \times 0.45} \\\\v_{max} = 2.97 \ m/s

Thus, the speed of the toy when it hits the ground is 2.97 m/s.

Learn more here: brainly.com/question/7562874

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MA_775_DIABLO [31]

Answer:

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Explanation:

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