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blagie [28]
4 years ago
13

A 1.60 mole sample of carbon dioxide, for which CP,m=37.1J⋅K−1⋅mol−1 at 298 K, is expanded reversibly and adiabatically from a v

olume of 3.45 L and a temperature of 298 K to a final volume of 47.0 L. Calculate the final temperature, q, w,DeltaH and DeltaU. Assume that Cp,m is constant over the temperature interval. (Show all work)

Chemistry
1 answer:
Lapatulllka [165]4 years ago
6 0

Answer:

Final Temperature = 140.09K

q = 0 (Adiabatic process)

w = 7272.95J

DeltaH = -9.37KJ

DeltaU = -7272.95J

Explanation:

The detailed mathematical derivation from the first principle, and the appropriate substitution is as shown in the attached file.

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3.47 g of the hydrated "double salt", ammonium iron (II) sulfate hexahydrate, FeSO4(NH4)2SO4*6H2O was dissolved in 200. mL of wa
Ostrovityanka [42]

Answer:

1.4 × 10^-4 M

Explanation:

The balanced redox reaction equation is shown below;

5Fe2+ + MnO4- + 8H+ --> 5Fe3+ +Mn2+ + 4H2O

Molar mass of FeSO4(NH4)2SO4*6H2O = 392 g/mol

Number of moles Fe^2+ in FeSO4(NH4)2SO4*6H2O = 3.47g/392g/mol = 8.85 × 10^-5 moles

Concentration of Fe^2+ = 8.85 × 10^-5 moles × 1000/200 = 4.425 × 10^-4 M

Let CA be concentration of Fe^2+ = 4.425 × 10^-4 M

Volume of Fe^2+ (VA)= 20.0 ml

Let the concentration of MnO4^- be CB (the unknown)

Volume of the MnO4^- (VB) = 12.6 ml

Let the number of moles of Fe^2+ be NA= 5 moles

Let the number of moles of MnO4^- be NB = 1 mole

From;

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

CB= CAVANB/VBNA

CB= 4.425 × 10^-4 × 20 × 1/12.6 × 5

CB = 1.4 × 10^-4 M

7 0
3 years ago
There’s a part two for this but I can’t fit it all in this image, if you know how to do this please help me out. I’m stuck on th
Alina [70]

Answer:

See explanation

Explanation:

According to the law of conservation of mass; the total mass of reactants on the left hand side of the reaction equation is equal to the total mass of products on the right hand side of the reaction equation.

Hence, the total mass of each atom on either side of the reaction equation should be exactly the same.

Since there are two atoms of oxygen on the reactants side, the total mass of oxygen = 16 amu * 2 = 32 amu

Since there are two oxygen atoms on the products side, total mass of oxygen = 16 amu * 2 = 32 amu

8 0
3 years ago
All changes in phase (solid-liquid-gas) are
tatuchka [14]

Answer:

States of matter

Explanation:

Three states of matter

7 0
3 years ago
Which material is the least likely to be recognized as a mixture by looking at it under a microscope? a suspension a colloid a h
viktelen [127]

Answer:

A homogeneous mixture for sure

4 0
3 years ago
Read 2 more answers
Does the density of an object depend on its size? Explain?.
evablogger [386]

No, the density of an object does not depend on its size.

A piece of glass with a volume of 10 cm³ may have a mass of 27 g. Its density is  

<em>D</em> = <em>m</em>/<em>V</em> = 27 g/10 cm³ = 2.7 g/cm³

A piece of the same type of glass with a volume of 20 cm³ will have a mass

of 54 g. Its density is  

<em>D</em> = <em>m</em>/<em>V</em> = 54 g/20 cm³ = 2.7 g/cm³

Thus, density does not change with the size of an object. Density is an <em>intensive property</em>.

3 0
3 years ago
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