Answer:
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Answer:
the speed of the center of mass of the two-particle system is 3.4 m/s.
Explanation:
Given that,
Mass of particle 1, m = 2 kg
Velocity of the particle 1, v = 4 m/s in +x direction
Mass of particle 2, m' = 3 kg
Velocity of the particle 2, v' = 5 m/s in +y direction.
The x -coordinate of velocity of the centre of mass is given by :
The y -coordinate of velocity of the centre of mass is given by :
So, the the speed of the center of mass of the two-particle system given by :
So, the speed of the center of mass of the two-particle system is 3.4 m/s.
Answer:
44.71 mi/h
11.17 mi
Explanation:
To express the velocity in the S.I. you use the following equality:
then, by replacing you obtain:
When the car has traveled while 15 minutes you have:
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TRANSLATION:
Para expresar la velocidad en el S.I., utiliza la siguiente igualdad:
entonces, al reemplazar, obtienes:
Cuando el automóvil ha viajado durante 15 minutos, tiene:
Answer:
0.0195 m
Explanation:
= density of hockey puck = 9.45 gcm⁻³ = 9450 kgm³
= diameter of hockey puck = 13 cm = 0.13 m
= height of hockey puck = 2.8 cm = 0.028 m
= density of mercury = 13.6 gcm⁻³ = 13600 kgm³
= depth of puck below surface of mercury
According to Archimedes principle, the weight of puck is balanced by the weight of mercury displaced by puck
Weight of mercury displaced = Weight of puck
The concept of momentum tells us that it is equivalent to the product between the mass and the velocity of the object, that is to say that in general it can be written as
Where,
m = mass
v = Velocity
Our values are given as,
Replacing we have that,
Therefore the magniude of the momentum of the pitched baseball is