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creativ13 [48]
3 years ago
10

Calculate the ph of a buffer that is 0.225 m hc2h3o2 and 0.162 m kc2h3o2. the ka for hc2h3o2 is 1.8 Ã 10-5. 4.60 9.26 4.74 4.89

9.11
Chemistry
2 answers:
Stella [2.4K]3 years ago
8 0

Answer:

The pH of the buffer solution is 4.60.

Explanation:

Concentration of acid = [HC_2H_3O_2]=0.225 M

Concentration of salt = [KC_2H_3O_2]=0.162 M

Dissociation constant = K_a=1.8 \times 10^{-5}

The pH of the buffer can be determined by Henderson-Hasselbalch equation:

pH=pK_a+\log\frac{[salt]}{[acid]}

pH=-\log[1.8 \times 10^{-5}]+\log\frac{0.162 M}{0.225 M}

pH = 4.60

The pH of the buffer solution is 4.60.

vivado [14]3 years ago
4 0

4.602

<h3>Further explanation</h3>

Given:

A buffer system consisting of 0.225 M HC₂H₃O₂ and 0.162 M KC₂H₃O₂.

The Ka for HC₂H₃O₂ is 1.8 x 10⁻⁵.

Question:

Calculate the pH of this buffer.

The Process:

Let us first observe the ionization reaction of the KC₂H₃O₂ salt below.

\boxed{ \ KC_2H_3O_2 \rightleftharpoons K^+ + C_2H_3O_2^- \ }

  • The KC₂H₃O₂ salt has valence = 1 according to the number of C₂H₃O₂⁻ ions as a weak part.
  • HC₂H₃O₂ and C₂H₃O₂⁻ are conjugate acid-base pairs
  • HC₂H₃O₂ and C₂H₃O₂⁻ form an acidic buffer system.

To calculate the specific pH of a given buffer, we need using The Henderson-Hasselbalch equation for acidic buffers:

\boxed{ \ pH = pK_a + log\frac{[A^-]}{[HA]} \ }

where,  

  • Ka represents the dissociation constant for the weak acid;
  • [A-] represent the concentration of the conjugate base (i.e. salt);  
  • [HA] is the concentration of the weak acid.

\boxed{ \ pH = pK_a + log\frac{[C_2H_3O_2^-]}{[HC_2H_3O_2]} \ }

\boxed{ \ pH = -log(1.8 \times 10^{-5}) + log\frac{[0.162]}{[0.225]} \ }

\boxed{ \ pH = 5-log \ 1.8 - 0.1427 \ }

\boxed{ \ pH = 5 - 0.2553 - 0.1427 \ }

\boxed{ \ pH = 4.602 \ }

Thus, the pH of this buffer equal to 4.602.

<h3>Learn more</h3>
  1. What is the pH of this buffer brainly.com/question/11437567
  2. The ratio of HCO₃⁻ to H₂CO₃ in an exhausted marathon runner whose blood pH is 7.2 brainly.com/question/3122018
  3. Calculate the pH of an acidic buffer system brainly.com/question/9079717
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Answer:

(i)The mole fractions are :

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Explanation:

The given equation is :

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  • B=\frac{1.4}{4.3} \\=0.3256
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(ii)

K=\frac{(P_C^3)(P_D^2)}{(P_A^2)(P_B)}

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P_A,P_B,P_C,P_D are the partial pressures of A,B,C,D respectively.

Total pressure = 1 bar .

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<em>P_C= 0.2093*1=0.2093</em>

<em>P_D= 0.3721*1=0.3721</em>

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(iii)

ΔG=-RTlnK\\

ΔG = -8.314*(273+25)*ln(0.4508)\\=1973.96J\\=1.974kJ

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Thereby, the rms speed results:

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