The marbles that are 'more energetic' fall out of the tray, in the same way particles have enough energy to escape and turn into a gas.
Answer:
at load 13114.85 N beam fail
Explanation:
given data
radius r = 6.7 mm
load = 2710 N
distance = 41 mm
length = 19 mm
to find out
At what load we expect this specimen to fracture
solution
we will first flexural strength that is
flexural strength = load × distance / πr³
flexural strength = 2710 × 41 × / π(6.7 ×)³
flexural strength = 117.592 MPa
we know that for cross section specimen
flexural strength = 3load × distance / 2bd²
put here these value
117.592 × N/m² = 3 load × 41 × / ( 2 × (19×)³)
load = 117.592 × × ( 2 × (19×)³) / ( 3 × 41 × )
load = 13114.85 N
so at load 13114.85 N beam fail
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Correct answer is A. Divide 300 by 75