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Vesna [10]
3 years ago
12

Find the momentum of a 25 kg object traveling at a speed of 4 m/s

Physics
1 answer:
White raven [17]3 years ago
4 0

Answer:

100 kg*m/s

Explanation:

P = m*v

= 25*4 = 100

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Sensory receptors pick up on senses from outside the body. To respond to the sense, what path does the information follow?
Radda [10]

Answer:

Follow that smell. SMELL: Originally thought to be present only in the nose, olfactory receptors exist in many locations in the body, including in the skin, heart, lungs, kidneys, muscles, and sperm. ...

Light relaxation. ...

A taste for pathogens

Explanation:

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7 0
2 years ago
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What is kirchoff s law???
kolbaska11 [484]
There are two laws named for Kirchhoff.  The both concern electrical circuits.
Here they are in my own words:

1).  The sum of the voltage drops around any closed loop in a circuit is zero.

2).  The sum of the currents at any single point in a circuit is zero.
8 0
2 years ago
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When a roller coaster gets to the bottom of a descent, describe the energy transfers and changes to energy stores that happen if
Feliz [49]

Answer:

its B

Explanation:

It's B & A at the same time because A. a roller coaster uses brakes to slow down and stop. B is the most reasonable answer. Because all roller coasters go up and over a second time over the hill, but they also slow down. But go with B.

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6 0
2 years ago
Electrons are accelerated in the picture tube of a television through potential difference of 8.00 * 10 ^ 3 V. (Use the values q
maria [59]

Answer:

\lambda=1.37\times 10^{-11}\ m

Explanation:

Give that,

The potential difference of the electrons, V=8\times 10^{3}\ V

We need to find the wavelength of the electrons.

Using the conservation of energy,

2meV=\dfrac{h^2}{\lambda^2}\\\\\lambda=\sqrt{\dfrac{h^2}{2meV}}

Put all the values,

\lambda=\sqrt{\dfrac{(6.63\times 10^{-34})^2}{2\times 9.1\times 10^{-31}\times 1.6\times 10^{-19}\times 8\times 10^3}}\\\\\lambda=1.37\times 10^{-11}\ m

So, the wavelength of the electrons is 1.37\times 10^{-11}\ m.

7 0
2 years ago
A circular 10-turn coil with a radius of 5.0 cm carries a current of 5 A. It lies in the xy plane in a uniform magnetic field =
Tju [1.3M]

Answer:

U = – 0.12J

Explanation:

Given N = 10 turns, I = 5A, r = 5×10-²m

B^ = 0.05 T iˆ+ 0.3 T kˆ

Magnitude of the magnetic field vector B = √(0.05²+0.3²) = 0.304T

Area = πr² = π(5×10-²)² = 7.85×10-³m²

Magnetic moment μ = NIA

μ = 10×5×7.85×10-³ = 0.3925Am²

U = -μ•B = –0.3925×0.304 = –0.12J

The sign is negative because the magnetic moment is aligned with the magnetic field.

3 0
2 years ago
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