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marta [7]
2 years ago
12

The atmospheric pressure above a swimming pool changes from 753 to 772 mm of mercury. the bottom of the pool is a rectangle (11

m cross product 21 m). by how much does the force on the bottom of the pool increase
Physics
2 answers:
Nikolay [14]2 years ago
8 0
Since we are talking about the pressure of water at a certain height, we can associate hydrostatic pressure or hydrostatic force. The formula relating this two is:

P = F/A
So,
F = P*A

To find the change of force, simply multiply the change in pressure to the cross-sectional area of the swimming pool. To report in terms of Newtons, let's convert mmHg to Pa (760 mmHg = 101325 Pa).

F = (772 - 753 mmHg)(101325 Pa/760 mmHg)(11 m × 21 m)
<em>F = 585,151.875 N</em>
Evgesh-ka [11]2 years ago
5 0
Change in pressure : 772-753 = 19 mm Hg 
Since 1 mm Hg = 133 Pa Hg
 Then, 19 mm Hg = 2527 Pa Hg
 Area of rectangular pool = L* B = 11 x 21 = 231 m^2
 To find the force, we multiply the area by the change in pressure: 2527 (231) = 583737N
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Calculate the orbital period of a dwarf planet found to have a semimajor axis of a = 4.0x 10^12 meters in seconds and years.
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Semimajor axis is 4\times 10^{12}\ m

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T^2=\dfrac{4\pi ^2}{6.67\times 10^{-11}\times 1.98\times 10^{30}}\times (4\times 10^{12})^3\\\\T=\sqrt{\dfrac{4\pi^{2}}{6.67\times10^{-11}\times1.98\times10^{30}}\times(4\times10^{12})^{3}}\\\\T=4.37\times 10^9\ s

Since,

1\ s=3.17\times 10^{-8}\ \text{years}\\\\4.37\times 10^9\ s=4.37\cdot10^{9}\cdot3.17\cdot10^{-8}\\\\4.37\times 10^9\ s=138.52\ \text{years}

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3 0
3 years ago
For safety reasons, a worker’s eye travel time in a certain operation must be separated from the manual elements that follow. Th
iogann1982 [59]

Answer:

The answer is 12.67 TMU

Explanation:

Recall that,

worker’s eyes travel  distance must be = 20 in.

The perpendicular distance from her eyes to the line of travel is =24 in

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Now,

We solve for the given problem.

Eye travel is = 15.2 * T/D

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so,

= 12.67 TMU

Therefore, the MTM -1 of normal time that should be allowed for the eye  travel element is = 12.67 TMU

7 0
3 years ago
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