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marta [7]
3 years ago
12

The atmospheric pressure above a swimming pool changes from 753 to 772 mm of mercury. the bottom of the pool is a rectangle (11

m cross product 21 m). by how much does the force on the bottom of the pool increase
Physics
2 answers:
Nikolay [14]3 years ago
8 0
Since we are talking about the pressure of water at a certain height, we can associate hydrostatic pressure or hydrostatic force. The formula relating this two is:

P = F/A
So,
F = P*A

To find the change of force, simply multiply the change in pressure to the cross-sectional area of the swimming pool. To report in terms of Newtons, let's convert mmHg to Pa (760 mmHg = 101325 Pa).

F = (772 - 753 mmHg)(101325 Pa/760 mmHg)(11 m × 21 m)
<em>F = 585,151.875 N</em>
Evgesh-ka [11]3 years ago
5 0
Change in pressure : 772-753 = 19 mm Hg 
Since 1 mm Hg = 133 Pa Hg
 Then, 19 mm Hg = 2527 Pa Hg
 Area of rectangular pool = L* B = 11 x 21 = 231 m^2
 To find the force, we multiply the area by the change in pressure: 2527 (231) = 583737N
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A) Z = 0.577 C +112.931

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Explanation:

For this case we want to create a function like this:

Z = a C + b

Where Z represent the degrees for the Z scale C the Celsius grades and  tha valus a and b parameters for the model.

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-195.8 °C = 0 °Z

1538 °C = 1000 °Z

Let's say that one point its (1538C, 1000 Z) and other one is (-195.8 C, 0Z)

So then we can calculate the slope for the linear model like this:

a = \frac{z_2 -z_1}{c_2 -c_1}= \frac{1000 Z- 0Z}{1538C -(-195.8 C)}=\frac{1000 Z}{1733.8 C}=0.577 \frac{Z}{C}

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0 = 0.577 (-195.8) + b

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So then our lineal model would be:

Z = 0.577 C +112.931

Part A

The boiling point of water is 100C so we just need to replace in the model and see what we got:

Z = 0.577*(100) +112.931=170.631 Z

Part B

For this case we have Z =100 and we want to solve for C, so we can do this:

Z-112.931 = 0.577 C

C=\frac{Z-112.931}{0.577}= \frac{100-112.931}{0.577}=-22.41 C

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For this case we know that K = C +273.15

And we can use the result from part B to solve for K like this:

K = -22.41 +273.15 =250.739 K

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