Answer:
Explanation:
Given that:
A circuit with a lagging 0.7 pf delivers 1500 watts and 2100VA
Here:
the initial power factor i.e cos θ₁ = 0.7 lag
θ₁ = cos⁻¹ (0.7)
θ₁ = 45.573°
Active power P = 1500 watts
Apparent power S = 2100 VA
What amount of vars must be added to bring the pf to 0.85
i.e the required power factor here is cos θ₂ = 0.85 lag
θ₂ = cos⁻¹ (0.85)
θ₂ = 31.788°
However; the initial reactive power 
= P×tanθ₁
the initial reactive power = 1500 × tan(45.573)
the initial reactive power = 1500 × 1.0202
the initial reactive power = 1530.3 vars
The amount of vars that must therefore be added to bring the pf to 0.85
can be calculated as:
Answer:
Explanation:
Kinetic energy of ball in motion = 1/2 m v² . Potential energy = 0
Let the minimum distance between the balls be d on collision.
Electric potential energy at that time= k Q²/d , Here kinetic energy is converted into potential energy . So
1/2 m v² = kQ²/d
d =2 k Q² / mv²,= 18 x 10⁹ x Q²/ m v².
The way I see it, depending on what the number represents, the number in the decimals spot could mean something significant. hope this helps :)
The ID, or Independent Variable, I think.
Radioisotopes is a atom with unstable nuclei. They also decay to change different from the electrons over time.
Hope it helped you.
-Charlie
