Answer:
78.96 g of NaC2H3O2
Explanation:
We are given;
- Volume of the solution as 350 mL
- Molarity of the solution as 2.75 M
- Molar mass of the solute NaC2H3O2 as 82.04 g/mol
We are required to determine the mass of the solute;
First we determine the number of moles;
Moles = Molarity × Volume
Therefore;
Moles of the solute = 2.75 M × 0.350 L
= 0.9625 moles
Second, we determine the mass
Mass = Moles × Molar mass
= 0.9625 moles × 82.04 g/mol
= 78.9635 g
= 78.96 g
Therefore, the mass of NaC2H3O2 needed is 78.96 g
<span>The answer I think is, 7.83E22.</span>
You can start by writing out the molecular formula of each molecule.
Aluminum (Al 3+) Phosphate (PO4 3-)
AlPO4
Nickel II (Ni 2+) sulfide (S 2-)
NiS
Aluminum Sulfide
Al2S3
Nickel Phosphate
Ni3(PO4)2
If you’re wondering, we get those charges by looking at the periodic table. The metals usually have a + charge based on their group number. The nonmetals usually - charge egual to 8 - their group number.
You then balance the ions by flipping the charges, dropping the signs, and adding them in as subscripts.
Now we can put it into an equation
AlPO4 + NiS —-> Al2S3 + Ni3(PO4)2
Balance by adding coefficients
2 AlPO4 + 3 NiS —-> Al2S3 + Ni3(PO4)2
Answer:
1. 0.0154mole of PbS
2. Double displacement reaction
Explanation:
First, let write a balanced equation for the reaction. This is illustrated below:
Pb(CH3COO)2 + H2S —> PbS + 2 CH3COOH
Molar Mass of Pb(CH3COO)2 = 207 + 2(12 + 3 + 12 + 16 +16) = 207 + 2(59) = 207 + 118 = 325g
Mass of Pb(CH3COO)2 = 5g
Number of mole = Mass /Molar Mass
Number of mole of Pb(CH3COO)2 = 5/325 = 0.0154mole
From the equation,
1mole of Pb(CH3COO)2 produced 1mole of PbS.
Therefore, 0.0154mole of Pb(CH3COO)2 will also produce 0.0154mole of PbS
2. The name of the reaction is double displacement reaction since the ions in the two reactants interchange to form two different products
A lot of heat like a lot no cap it’s gonna he a lot
