HELP PLEASE! What is the power of a kitchen if it can preform 2000 joules of work in 5 seconds
1 answer:
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Answer:
The average force that brings the car to rest is 175000N
Explanation:The mass of the car, m = 1000 kg
Initial speed, u = 14 m/s
Final speed, v = 0 m/s (Since the car comes to a stop)
The time taken, t = 8 x 10^-2 s
The average force is calculated as:
The average force that brings the car to rest is 175000N
We can solve this problem using <span>Hagen–Poiseuille equation. Derivation of this equation is a bit complicated so I will just write down the equation.
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This equation gives you the pressure drop <span>in an </span>incompressible<span> and </span>Newtonian<span> fluid in </span>laminar flow<span> flowing through a long cylindrical pipe of the constant cross section.
L is the length of the cylinder, Q is the volumetric flow rate, R is the radius of the pipe, and
is dynamic viscosity.
Dynamic viscosity of water at 20 Celsius is 0.001 PaS.
Now we can calculate the pressure drop:
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This equation gives you the pressure drop <span>in an </span>incompressible<span> and </span>Newtonian<span> fluid in </span>laminar flow<span> flowing through a long cylindrical pipe of the constant cross section.
L is the length of the cylinder, Q is the volumetric flow rate, R is the radius of the pipe, and
Dynamic viscosity of water at 20 Celsius is 0.001 PaS.
Now we can calculate the pressure drop:
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Answer:
Part a: <em>The total amount of energy transfer by the work done is 54.81 kJ.</em>
Part b: <em>The total amount of energy transfer by the heat is 54.81 kJ</em>
Explanation:
Mass of Carbon Dioxide is given as m1=3 kg
Pressure is given as P1=3 bar =300 kPA
Volume is given as V1=0.5 m^3
Pressure in tank 2 is given as P2=2 bar=200 kPa
T=290 K
Now the Molecular weight of is given as
M=44 kg/kmol
the gas constant is given as
Volume of the tank is given as
Final mass is given as
Mass of the CO2 moved to the cylinder
The initial mass in the cylinder is given as
The mass after the process is
Now the volume 2 of the cylinder is given as
Part a:
So the Work done is given as
<em>The total amount of energy transfer by the work done is 54.81 kJ.</em>
Part b:
The total energy transfer by heat is given as
As the temperature is constant thus change in internal energy is 0.
<em>The total amount of energy transfer by the heat is 54.81 kJ</em>