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3 years ago

5

What happens when an electron absorbs a photon

1 answer:

nordsb [41]3 years ago

7 0

Explanation:

A small piece of energy is called as Electron. It cannot be broken down further into smaller pieces. Photon is a basic unit of light. Photons always travel. They are in a continuous motion. So when electron needs energy, They absorb light. The light is absorbed or emitted in the form of photons. Each photon contains energy which is absorbed by the electron to gain its energy. After absorbing the photon, electron moves towards a higher energy level. So when an electron absorbs a photon, energy is gained by the electron.

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What is the fastest motion that can be measured in any frame of reference?

Furkat [3]

Answer: The answer is D: 300,000km/s

Explanation:

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2 years ago

A 900 kilogram compact car was stopped at a traffic light when an 1800 kilogram luxury sedan struck it from behind the two cars

SOVA2 [1]

The answer is B. 22.7 kg-m/s

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3 years ago

A box of mass 26 kg is initially at rest on a flat floor. The coefficient of kinetic friction between the box and the floor is 0

Kazeer [188]

Answer:

$\Delta K = 52J$

Explanation:

The change in kinetic energy will be simply the difference between the final and initial kinetic energies: $\Delta K=K_f-K_i$

We know that the formula for the kinetic energy for an object is:

$K=\frac{mv^2}{2}$

where <em>m </em>is the mass of the object and <em>v</em> its velocity.

For our case then we have:

$\Delta K = K_f-K_i=\frac{mv_f^2}{2}-\frac{mv_i^2}{2}=\frac{m(v_f^2-v_i^2)}{2}$

Which for our values is:

$\Delta K = \frac{m(v_f^2-v_i^2)}{2} = \frac{(26Kg)((2m/s)^2-(0m/s)^2)}{2} = 52J$

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3 years ago

A bowling ball is rolling in a straight line toward the pins at a speed of 2.2 m/s. Its momentum is 4.75 kg*m/s. What is the

Thepotemich [5.8K]

Answer: m= 2.16 kg

Explanation: Momentum is expressed in the following formula:

p = mv

Derive to find m:

m = p / v

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3 years ago

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A diver is on a board 1.80 m above

Virty [35]

Answer:

v = 6.95 m/s

Explanation:

Given that,

A diver is on a board 1.80 m above the water, s = 1.8 m

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$v^2-u^2=2gs\\\\v=\sqrt{u^2+2gs} \\\\v=\sqrt{(3.62)^2+2(9.8)(1.8)} \\\\v=6.95\ m/s$

So, she will hit the water with a speed of 6.95 m/s.

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3 years ago

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