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3 years ago

What happens when an electron absorbs a photon

Physics

1 answer:

nordsb [41]3 years ago

7 0

Explanation:

A small piece of energy is called as Electron. It cannot be broken down further into smaller pieces. Photon is a basic unit of light. Photons always travel. They are in a continuous motion. So when electron needs energy, They absorb light. The light is absorbed or emitted in the form of photons. Each photon contains energy which is absorbed by the electron to gain its energy. After absorbing the photon, electron moves towards a higher energy level. So when an electron absorbs a photon, energy is gained by the electron.

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An initially stationary object experiences an acceleration of 6 m/s2 for a time of 15 s. How far will it travel during that time

Tju [1.3M]

Answer:

675m

Explanation:

Given parameters:

Initial velocity = 0m/s

Acceleration = 6m/s²

Time = 15s

Unknown:

Distance traveled by the body = ?

Solution:

To solve this problem; we use the expression;

S = ut + $\frac{1}{2}$ at²

Where u is the initial velocity

t is the time

a is the temperature

Insert the parameters and solve;

S = 0 x 15 + $\frac{1}{2}$ x 6 x 15²

S = 675m

5 0

2 years ago

A truck pulls a block 8 meters across a level surface at a force of 216 N over the course of 12 seconds. How much power did the

iren [92.7K]

Answer:

work = 1728

Power = 134

Explaination:

by using the formula,

Work(W)= Force(F)×Distance(D)

Power(P)= Work(W)/Time taken(T)

4 0

3 years ago

What is the car's speed at the bottom of the dip?The passengers in a roller coaster car feel 50% heavier thantheir true weight a

Rashid [163]

Answer:

v = 14 m/s

Explanation:

given,

radius of dip = 40 m

The passengers in a roller coaster car feel 50% heavier than their true weight.

Apparent weight

$A = W + \dfrac{W}{2}$

$A =\dfrac{3W}{2}$

$A =\dfrac{3mg}{2}$

When the car is at the bottom, the weight will be acting downwards and the centripetal force will also be acting downward where as Normal force which is apparent weight will be acting in upward direction.

now,

$N = m g + \dfrac{mv^2}{r}$

$\dfrac{3mg}{2} = m g + \dfrac{mv^2}{r}$

$\dfrac{mg}{2} = \dfrac{mv^2}{r}$

$v = \sqrt{\dfrac{rg}{2}}$

$v = \sqrt{\dfrac{40\times 9.8}{2}}$

v = 14 m/s

8 0

2 years ago

A person throws a pumpkin at a horizontal speed of 4.0 — off a cliff. The pumpkin travels 9.5 m horizontally

emmainna [20.7K]

Complete Question

A person throws a pumpkin at a horizontal speed of 4.0 m/s off a cliff. The pumpkin travels 9.5m horizontally before it hits the ground. We can ignore air resistance.What is the pumpkin's vertical displacement during the throw? What is the pumpkin's vertical velocity when it hits the ground?

Answer:

The pumpkin's vertical displacement is $H = 27 .67 \ m$

The pumpkin's vertical velocity when it hits the ground is $v_v__{f}} = 23.298 \ m/s$

Explanation:

From the question we are told that

The horizontal speed is $v_h = 4 m/s$

The horizontal distance traveled is $d = 9.5 \ m$

The horizontal distance traveled is mathematically represented as

$S = v_h * t$

Where t is the time taken

substituting values

$9.5 = 4 * t$

=> $t = \frac{9.5}{4}$

$t = 2.38 \ sec$

Now the vertical displacement is mathematically represented as

$H = v_v t + \frac{1}{2} a_v t^2$

now the vertical velocity before the throw is zero

$H = 0 + \frac{1}{2} (9.8) * (2.375)^2$

$H = 27 .67 \ m$

Now the final vertical velocity is mathematically represented as

$v_v__{f}} = v_v + at$

substituting values

$v_v__{f}} = 0 + (9.8)* (2.375)$

$v_v__{f}} = 23.298 \ m/s$

7 0

2 years ago

Why does a typhoon hit a location twice?

Natalka [10]

The reason a location usually doesn't get a storm within a few weeks of another one is more because of the general odds. They're low. And they're lower in Texas than in Florida. ... There are many locations a storm can develop and track

7 0

2 years ago