Section of two thermometers are shown. The thermometer on the left is labeled A and the thermometer on the right is labeled B. T
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As per the question,the current amplitude is given as i= -2.7 micro ampere
i.e -2.7 ×
as per the question the time is given as t=1.15s
we know that
hence q=i×t
hence the total charge passing through this point is given as
q= -2.7×× 1.15
= -3.105×
we know that q=ne where n is the number of electrons and e is the charge of electron
we have e= -1.602× coulomb
hence number of electrons n=
= 3.105××
=1.93820×
The wavelength of the light is 590nm
wavelength of the light=λ
Given,
The equation for a diffraction grating to use here is dsinθ = mλ
d=1/610 lines per mm=1.639*, m=1, θ=21.
λ=1.639* * sin21.
/1 =590nm
The wavelength, which in physics refers to the length over which a periodic wave repeats, is its spatial period. It is the distance between two successive corresponding wave points of the same phase, such as two neighbouring crests, troughs, or zero crossings, and it is a feature of both travelling waves and standing waves, as well as other spatial wave patterns. The spatial frequency is defined as the wavelength's inverse. The Greek letter lambda, or "wavelength," is frequently used to represent it. Additionally, sinusoidal wave envelopes, modulated waves, and waves created by the interference of several sinusoids are also commonly referred to as having a wavelength.
You measure an angle of 21. 1 when the light passes through a grating with 610 lines per mm. what is the wavelength of the light?
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