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pishuonlain [190]
4 years ago
14

What is the electric field in N/C) at a point where the force on a -2.1 x 10-5 C charge is (4.31 -6.89) x 10-6 N?

Physics
1 answer:
krek1111 [17]4 years ago
8 0

Answer: 0.123 N/C

Explanation: In order to solve this question we have to use the  electric  Force on a particle produced by an electric field which is given by:

F=q*E

so E=F/q= -2,58* 10^-6/-2.1*10^-5= 0.123 N/C

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