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bazaltina [42]
3 years ago
10

BEST ANSWER WILL BE BRANLIEST!! 70 POINTS!!

Physics
1 answer:
musickatia [10]3 years ago
3 0

Answer:

Explanation:

The speed of light in a vacuum is approximately 3×10⁸ m/s.

In water with η=1.33:

v = (3×10⁸ m/s) / 1.33

v = 2.26×10⁸ m/s

In glass with η=1.50:

v = (3×10⁸ m/s) / 1.50

v = 2.00×10⁸ m/s

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If the axes of the two cylinders are parallel, but displaced from each other by a distance d, determine the resulting electric f
Novay_Z [31]

Answer:

E =  ρ ( R1²) / 2 ∈o R

Explanation:

Given data

two cylinders are parallel

distance = d

radial distance = R

d < (R2−R1)

to find out

Express answer in terms of the variables ρE, R1, R2, R3, d, R, and constants

solution

we have two parallel cylinders

so area is 2 \pi R × l

and we apply here gauss law that is

EA = Q(enclosed) / ∈o   ......1

so first we find  Q(enclosed) = ρ Volume

Q(enclosed) = ρ ( \pi R1² × l )

so put all value in equation 1

we get

EA = Q(enclosed) / ∈o

E(2 \pi R × l)  = ρ ( \pi R1² × l ) / ∈o

so

E =  ρ ( R1²) / 2 ∈o R

6 0
4 years ago
A certain corner of a room is selected as the origin of a rectangular coordinate system. If a fly is crawling on an adjacent wal
lisov135 [29]

Answer:

S=2.693m

Explanation:

Let point O be the origin of the room and the fly is crawling at point P as shown in the attached photo:

#Distance of the fly from the corner of the room is defined as:

OP=S=\sqrt{{(x_1-x_0)^2+(y_1+y_0)^2}

#Substitute the coordinate values in the above equation:

S=\sqrt{{(2.6m-0m)^2+(0.7m-0m)^2}}\\=\sqrt{7.25}\\=2.693m

Hence, the distance of the fly from the corner of the room is 2.693m

6 0
4 years ago
A 60 W light bulb has a resistance of 880 Ω
Andreas93 [3]

<h2>\bf{ \underline{Given:- }}</h2>

\sf{• \:  Power \:  (P) = 60 \:  w}

\sf{•  \: Resistance \:  (R) = 880  \: Ω}

\\

<h2>\bf{ \underline{To \:  Find :- }}</h2>

\sf• \:  The  \: Current \:  (I).

\\

\huge\bf{ \underline{ Solution :- }}

\sf We  \: know  \: that,

\bf \red {\bigstar{ \: P = I^{2} R}}

\rightarrow \sf 60 = I^{2}  \times 880

\rightarrow \sf  \frac{60}{880} = I^{2}

\rightarrow \sf  I^{2}   = 0.0681

\rightarrow \sf  I   =  \sqrt{0.0681}

\rightarrow \sf  I   =  0.261 \:  \: (approx.)

\\

\bf The \:   \: value \:  \:  of \:  \:  I  \:  \:   is \:  \:  0.261 \:  \: Amps. \:  \: (approx.)

7 0
3 years ago
A cake is removed from a 350◦F oven and placed on a cooling rack in a 70◦F room. After 30 minutes the cake is 200◦F. When will i
galben [10]

Answer:

350 F to 100 F it take approx 87.33 min  

Explanation:

given data

oven = 350◦F

cooling rack = 70◦F

time = 30 min

cake = 200◦F

solution

we apply here Newtons law of cooling  

\frac{dT}{dt} = -k(T-Ta)

\frac{dy}{dt} = \frac{d}{dt} (T(t) -Ta)

= \frac{dT}{dt} -\frac{dTa}{dt} =\frac{dT}{dt} = -k(T-Ta)

-ky \frac{dy}{dt} = -ky

T(t) -Ta = (To -Ta) e^{-kt} T(t) = Ta+ (To -Ta)  e^{-kt}

put her value for time 30 min and T(t) = 200◦F and To =350◦F  and Ta = 70◦F

so here

200 = 70 + ( 350 - 70 ) e^{-k30}

k = 0.025575

so here for  T(t) = 100F

100 = 70 + ( 350 - 70 ) e^{-0.025575*t}

time = 87.33 min

so here 350 F to 100 F it take approx 87.33 min  

5 0
4 years ago
Which states the purpose of an experiment?
Whitepunk [10]
B; to produce a hypothesis.

6 0
3 years ago
Read 2 more answers
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